A stone is dropped from rest into a well. The sound of the splash is heard exactly 1.10 s later. Find the depth of the well if the air temperature is 11.0°C.  m

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A stone is dropped from rest into a well. The sound of the splash is heard exactly 1.10 s later. Find the depth of the well if the air temperature is 11.0°C.
 m

Expert Solution
Step 1

The formula for speed of sound in air is given by

v=331ms1+TC273°C=331ms1+11°C273°C=337.6ms

The depth of the well is given by

h=gt221

Here, t is the time for the stone to fall in to the well.

The time for the sound to travel back up the well is given by

t'=hv

Here,  t' is the time taken for the sound to travel back up the well.

The time taken for the sound to travel up the well is difference between

t' = 1.10 - t

Use t'=hv in the above equation.

hv=1.10-tgt22v=1.10-tgt22v+t-1.10=0

Substitute 9.8ms2 for g , and  337.6msfor v in the above equation for t .

9.8ms2t22337.6ms+t-1.10=00.0145t2+t-1.10=0

Solve the above quadratic equation.

t=1.08mor-70.04m

 

 

 

 

 

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