Answered: A sticky substance that upon dissolving…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A sticky substance that upon dissolving in water, is found to be a nonelectrolyte, has a concentration of 0.857 M. Convert the concentration to molality. The density of the solution is 1.355 g/mL. The molar mass of the compound is 139.9 g/mol. Report your answer to the thousandths place and do not include units.

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$M o l a r i t y = N u m b e r o f m o l e s o f s o l u t e / v o l u m e o f s o \ln i n L m o l a l i t y = n o . o f m o l e s o f s o l u t e / m a s s o f s o l v e n t i n K g M o l a r i t y = 0.857 M M o l a r m a s s o f c o m p o u n d = 139.9 g / m o l D e n s i t y o f s o l u t i o n = 1.355 g / m l A s s u m e t h e n o . o f m o l e s = 0.857 m o l p u t t i n g i n m o l a r i t y e q u a t i o n w e g e t V = 1 L = 1000 m l m a s s o f s o l u t e = n o . o f m o l e s \times m o l a r m a s s = 0.857 \times 139.9 = 119.89 g$

$D e n s i t y = m a s s o f s o l u t i o n / v o l u m e o f s o l u t i o n 1.355 = m / 1000 m a s s o f s o l u t i o n = 1355 g m a s s o f s o l u t i o n = m a s s o f s o l u t e + m a s s o f s o l v e n t 1355 = 119.89 + m a s s o f s o l v e n t m a s s o f s o l v e n t = 1355 - 119.89 = 1235.11 g = 1.23 k g$

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