A step-up transformer connected to a 110-V line is used to supply a hydrogen-gas discharge tube with 5.0 kV (rms). The tube dissipates 105 W of power. (a) What is the ratio of the number of turns in the secondary winding to the number of turns in the primary winding? (b) What are the rms currents in the primary and secondary windings? (c) What is the effective resistance seen by the 110-V source? Hint a. The ratio of number of turns in the secondary winding (N2) to the primary winding (N1) is N2 / N1 = b. The rms current in the primary winding is A; the rms current in the secondary winding is А. c. The 110-V source sees effective resistance of Ω.

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**Problem Statement:**

A step-up transformer connected to a 110-V line is used to supply a hydrogen-gas discharge tube with 5.0 kV (rms). The tube dissipates 105 W of power. 

**Questions:**

(a) What is the ratio of the number of turns in the secondary winding to the number of turns in the primary winding?

(b) What are the rms currents in the primary and secondary windings?

(c) What is the effective resistance seen by the 110-V source?

**Interactive Input Fields:**

a. The ratio of number of turns in the secondary winding (\(N_2\)) to the primary winding (\(N_1\)) is \(\frac{N_2}{N_1} =\) [Input Field].

b. The rms current in the primary winding is [Input Field] A; the rms current in the secondary winding is [Input Field] A.

c. The 110-V source sees effective resistance of [Input Field] \(\Omega\). 

**Note:** There is a "Hint" button available for assistance.
Transcribed Image Text:**Problem Statement:** A step-up transformer connected to a 110-V line is used to supply a hydrogen-gas discharge tube with 5.0 kV (rms). The tube dissipates 105 W of power. **Questions:** (a) What is the ratio of the number of turns in the secondary winding to the number of turns in the primary winding? (b) What are the rms currents in the primary and secondary windings? (c) What is the effective resistance seen by the 110-V source? **Interactive Input Fields:** a. The ratio of number of turns in the secondary winding (\(N_2\)) to the primary winding (\(N_1\)) is \(\frac{N_2}{N_1} =\) [Input Field]. b. The rms current in the primary winding is [Input Field] A; the rms current in the secondary winding is [Input Field] A. c. The 110-V source sees effective resistance of [Input Field] \(\Omega\). **Note:** There is a "Hint" button available for assistance.
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