A steel tube (E = 200 GPa) with a 32-mm outer diameter and a 4-mm wall thickness is placed in a vise, which is adjusted so that its jaws just touch the ends of the tube without exerting pressure on them. The two forces shown are then applied to the tube. After these forces are applied, the vise is adjusted to decrease the distance between its jaws by 0.2 mm. It is given that P = 34 kN. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 80 mm 80 mm 80 mm- 30 kN ermine the forces exerted by the vise on the tube at A and D. force exerted by the vise on the tube at A is force exerted by the vise on the tube at Dis 71..5 KN →→→ kN Determine the change in length of portion BC of the tube. The change in length of portion BC of the tube is -( mm.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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A steel tube (E = 200 GPa) with a 32-mm outer diameter and a 4-mm wall thickness is placed in a vise, which
is adjusted so that its jaws just touch the ends of the tube without exerting pressure on them. The two forces
shown are then applied to the tube. After these forces are applied, the vise is adjusted to decrease the
distance between its jaws by 0.2 mm. It is given that P = 34 kN.
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
-80 mm +-80 mm 80 mm-
B
30 kN
D
Determine the forces exerted by the vise on the tube at A and D.
The force exerted by the vise on the tube at A is 71..5 KN→→→
The force exerted by the vise on the tube at Dis
kN ←.
Determine the change in length of portion BC of the tube.
The change in length of portion BC of the tube is
mm.
Transcribed Image Text:A steel tube (E = 200 GPa) with a 32-mm outer diameter and a 4-mm wall thickness is placed in a vise, which is adjusted so that its jaws just touch the ends of the tube without exerting pressure on them. The two forces shown are then applied to the tube. After these forces are applied, the vise is adjusted to decrease the distance between its jaws by 0.2 mm. It is given that P = 34 kN. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. -80 mm +-80 mm 80 mm- B 30 kN D Determine the forces exerted by the vise on the tube at A and D. The force exerted by the vise on the tube at A is 71..5 KN→→→ The force exerted by the vise on the tube at Dis kN ←. Determine the change in length of portion BC of the tube. The change in length of portion BC of the tube is mm.
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