A steel cylindrical tank must hold 7110 gal of dyed water for a cloth process. Due to space constraints, the cylindrical tank is made 11.0 ft in diameter.  How y'all must the tank be? (Water weighs 8.34 lb/gal and 62.4 lb/fr^3.)

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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A steel cylindrical tank must hold 7110 gal of dyed water for a cloth process. Due to space constraints, the cylindrical tank is made 11.0 ft in diameter. 
How y'all must the tank be? (Water weighs 8.34 lb/gal and 62.4 lb/fr^3.) 

### Volume and Capacity Calculations for Cylindrical Tanks

**Volume Calculation:**
To calculate the volume of a cylindrical tank, we use the formula:

\[ V = \pi r^2 h \]

Where:
- \( V \) is the volume
- \( r \) is the radius of the cylinder
- \( h \) is the height of the cylinder

In the context of the problems presented:

1. **First Problem:**
   - Given the volume \( V = 963 \, \text{m}^3 \).
   - There's an illustration of a cylindrical tank with a height of \( 17.9 \, \text{m} \).

2. **Second Problem:**
   - A steel cylindrical tank needs to hold \( 7110 \, \text{gal} \) of dyed water.
   - Due to space constraints, the cylindrical tank has a diameter of \( 11.0 \, \text{ft} \).

   Since the diameter is given, the radius \( r \) can be found using:

   \[ r = \frac{\text{Diameter}}{2} = \frac{11.0 \, \text{ft}}{2} = 5.5 \, \text{ft} \]

   To find the height \( h \) of the tank, we know:
   - Water weighs \( 8.34 \, \text{lb/gal} \)
   - Water has a density of \( 62.4 \, \text{lb/ft}^3 \)

3. **Third Problem:**
   - An oil filter for a small automobile is cylindrical with a radius of \( 1.80 \, \text{in} \) and height \( 3.60 \, \text{in} \).

     The volume \( V \) can be calculated using:

     \[ V = \pi r^2 h \]
     \[ V = \pi (1.80 \, \text{in})^2 (3.60 \, \text{in}) \]

### Diagram Interpretation:
- The first diagram depicts a cylindrical tank with a height labeled as \( 17.9 \, \text{m} \).

### Questions to Answer:

1. **Height of the Steel Cylindrical Tank:**
   How tall must the tank be to hold \( 7110 \,
Transcribed Image Text:### Volume and Capacity Calculations for Cylindrical Tanks **Volume Calculation:** To calculate the volume of a cylindrical tank, we use the formula: \[ V = \pi r^2 h \] Where: - \( V \) is the volume - \( r \) is the radius of the cylinder - \( h \) is the height of the cylinder In the context of the problems presented: 1. **First Problem:** - Given the volume \( V = 963 \, \text{m}^3 \). - There's an illustration of a cylindrical tank with a height of \( 17.9 \, \text{m} \). 2. **Second Problem:** - A steel cylindrical tank needs to hold \( 7110 \, \text{gal} \) of dyed water. - Due to space constraints, the cylindrical tank has a diameter of \( 11.0 \, \text{ft} \). Since the diameter is given, the radius \( r \) can be found using: \[ r = \frac{\text{Diameter}}{2} = \frac{11.0 \, \text{ft}}{2} = 5.5 \, \text{ft} \] To find the height \( h \) of the tank, we know: - Water weighs \( 8.34 \, \text{lb/gal} \) - Water has a density of \( 62.4 \, \text{lb/ft}^3 \) 3. **Third Problem:** - An oil filter for a small automobile is cylindrical with a radius of \( 1.80 \, \text{in} \) and height \( 3.60 \, \text{in} \). The volume \( V \) can be calculated using: \[ V = \pi r^2 h \] \[ V = \pi (1.80 \, \text{in})^2 (3.60 \, \text{in}) \] ### Diagram Interpretation: - The first diagram depicts a cylindrical tank with a height labeled as \( 17.9 \, \text{m} \). ### Questions to Answer: 1. **Height of the Steel Cylindrical Tank:** How tall must the tank be to hold \( 7110 \,
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