A statistics professor wanted to see if there was any difference in the final averages of students using one of 3 methods of instruction. Each method that was used had 20 students in computing the values. The table shows the summary data: Method Mean Standard deviation Online only 71.5 3.4 On campus only 82.4 4.1 Hybrid (both online 76.0 4.8 and on campus aspects used)

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Subparts A,B,C,D, and E
E. What is the decision?
O Not all population means are the same.
All population means are different.
All population means are equal.
Transcribed Image Text:E. What is the decision? O Not all population means are the same. All population means are different. All population means are equal.
A statistics professor wanted to see if there was any difference in the final averages of students using one of 3
methods of instruction. Each method that was used had 20 students in computing the values. The table
shows the summary data:
Method
Mean
Standard
deviation
71.5 3.4
Online only
On campus only
82.4 4.1
Hybrid (both online
76.0 4.8
and on campus
aspects used)
A. What type of test is this?
O Chi square test of independence
ANOVA
Chi square goodness of fit
O Correct answer is not give
B. How many degrees of freedom are there?
Onumerator 2, denominator 60
O numerator 2, denominator 57
O numerator 3, denominator 57
Onumerator 3, denominator 60
correct answer is not given
C. What is the critical value at 5% level of significance?
What is the test statistic? Keep working numbers to as many decimal places as the TI shows, but round
final answer to 3 decimal places.
Transcribed Image Text:A statistics professor wanted to see if there was any difference in the final averages of students using one of 3 methods of instruction. Each method that was used had 20 students in computing the values. The table shows the summary data: Method Mean Standard deviation 71.5 3.4 Online only On campus only 82.4 4.1 Hybrid (both online 76.0 4.8 and on campus aspects used) A. What type of test is this? O Chi square test of independence ANOVA Chi square goodness of fit O Correct answer is not give B. How many degrees of freedom are there? Onumerator 2, denominator 60 O numerator 2, denominator 57 O numerator 3, denominator 57 Onumerator 3, denominator 60 correct answer is not given C. What is the critical value at 5% level of significance? What is the test statistic? Keep working numbers to as many decimal places as the TI shows, but round final answer to 3 decimal places.
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