(a) State Raoult’s law for a solution containing volatile components. How does Raoult’s law become a special case of Henry’s law?(b) 1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. Find the molar mass of the solute. (Kyfor benzene = 5.12 K kg mol-1)

Chemistry: The Molecular Science
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Chapter13: The Chemistry Of Solutes And Solutions
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(a) State Raoult’s law for a solution containing volatile components. How does Raoult’s law become a special case of Henry’s law?
(b) 1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. Find the molar mass of the solute. (Kyfor benzene = 5.12 K kg mol-1)

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