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A state charges polluters an annual fee of $50 per ton for each ton of pollutant emitted into the atmosphere, up to a maximum of 6,000 tons. No fees are charged for emissions beyond the 6,000-ton limit. Write a piecewise definition of the fees F(x) charged for the emission of x tons of pollutant in a year. What is the limit of F(x) as x approaches 6,000 tons? As x approaches 9,000 tons?

A state charges polluters an annual fee of $50 per ton for each ton of pollutant emitted into the atmosphere, up to a maximum of 6,000 tons. No fees are charged for emissions beyond the 6,000-ton limit. Write a piecewise definition of the fees F(x) charged for the emission of x tons of pollutant in a year. What is the limit of F(x) as x approaches 6,000 tons? As x approaches 9,000 tons?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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A state charges polluters an annual fee of $50 per ton for each ton of pollutant emitted into the atmosphere, up to a maximum of 6,000 tons. No fees are charged for emissions beyond the 6,000-ton limit. Write a piecewise definition of the fees F(x) charged for the emission of x tons of pollutant in a year. What is the limit of F(x) as x approaches 6,000 tons? As x approaches 9,000 tons? Write the piecewise definition of the fees F(x) charged for the emission of x tons of pollutant in a year. if 0 < x≤6,000 if x>6,000 (Simplify your answers.) F(x) = {
Transcribed Image Text:A state charges polluters an annual fee of $50 per ton for each ton of pollutant emitted into the atmosphere, up to a maximum of 6,000 tons. No fees are charged for emissions beyond the 6,000-ton limit. Write a piecewise definition of the fees F(x) charged for the emission of x tons of pollutant in a year. What is the limit of F(x) as x approaches 6,000 tons? As x approaches 9,000 tons? Write the piecewise definition of the fees F(x) charged for the emission of x tons of pollutant in a year. if 0 < x≤6,000 if x>6,000 (Simplify your answers.) F(x) = {
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