Answered: A star has an element in its atmosphere…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A star has an element in its atmosphere that normally emits a line of frequency fs = 7.5 x 10^14 vib/s. If astronomers measure the frequency of this line to be fo = 7.7 x 10^14 vib/s, then how fast are the Earth and this star traveling relative to each other? Remember that the correct equation for the speed v is given by v = [(fo^2 - fs^2) / (fo^2 + fs^2)] c Remember fo^2 means "fo squared."

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Given data

The frequency of the star is: f_s = 7.5 x 10¹⁴ Vib/s

The measured frequency by the astronomers is: f_o = 7.7 x 10¹⁴ Vib/s

The expression for the speed is given as:

$v = (\frac{{(f_{o})}^{2} - {(f_{s})}^{2}}{{(f_{o})}^{2} + {(f_{s})}^{2}}) c$

The speed of the light is: c = 3 x 10⁸ m/s.

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