15 MCQSA standing wave with wavelength A= 1.2 m and frequency f-100 Hz is generatedon a stretched cord. For an element of the cord at x =0.5 m, the maximumtransverse velocity is v(y,max) = 2t m/s. The amplitude A of each of the individualwaves producing the standing wave is:%3DO 0.02 mO0.0125 mO 0.025 mO 0.01 mO 0.03 mfixed

Standing waves are considered stationary waves and they are formed when the two waves of equal…

A standing wave with wavelength A= 1.2 m and frequency f 100 Hz is generated on a stretched cord. For an element of the cord at x =0.5 m, the maximum FO transverse velocity is v(y,max) = 2t m/s. The amplitude A of each of the individual waves producing the standing wave is: %D O 0.02 m O 0.0125 m O 0.025 m O 0.01 m

A standing wave with wavelength A= 1.2 m and frequency f 100 Hz is generated on a stretched cord. For an element of the cord at x =0.5 m, the maximum FO transverse velocity is v(y,max) = 2t m/s. The amplitude A of each of the individual waves producing the standing wave is: %D O 0.02 m O 0.0125 m O 0.025 m O 0.01 m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A standing wave on a stretched string fixed at both ends is described by: y(x,t) = 0.1 sin(2Ttx) cos(100Tt). The string has a length L = 1 m. For t > 0, an element on the string located at x = 0.75 cm would have a zero speed for the first time at: O t= 0.02 sec O t= 0.01 sec O t= 0.025 sec t = 0.015 sec O t= 0.005 sec
A standing wave on a string is generated over the 1.65m length of the string. The mass of the string is 26.4g. The standing wave is generated by a 60Hz oscillator. Calculate the tension required to create a standing wave with the following number of nodes: 3 4 5 6
A traveling wave on a taut string with a tension force T, is given by the wave function: y(x,t) = 0.05sin(Ttx-100Tt), where x and y are in meters and t is in seconds. If the linear mass density of the string is given by µ = 0.01 kg/m, then the tension force on the string is, O 25 N O 10 N O 100 N O 0.5 N O 1N
A travelling wave on a taut string is given by the wave function: y(x,t) = 0.1sin(2rtx - 200t), where x and y are in meters and t is in seconds. The linear mass density of the string is u = 300 g/m, and the string is 7m long. The total energy on the string is: 945 J O 60 J O 134 J O 19 J 420 J
O y_1 (x,t)=1mm sin(2rx-20Ttt) and y_2 (x,t)=1mm sin(2rx+20rtt) A sinusoidal transverse wave has a wavelength of 2.8 m. It takes 0.2 s for an element of the string at a position x to move from the maximum position of ymax = 0.03 m to the equilibrium position y 0. What is the period of the wave, T, and the wave speed, v? 0.4 sec; 7 m/s O 0.8 sec; 14 m/s O 0.8 sec; 3.5 m/s 0.4 sec; 28 m/s A taut string fixed at both ends is driven by an oscillator at a constant frequency of 100 Hz. The amplitude
A traveling wave on a taut string with a tension force T, is given by the wave function: y(x,t) = 0.05sin(Ttx-100rt), where x and y are in meters and t is in seconds. If the linear mass density of the string is given by u = 0.01 kg/m, then the tension force on the string is, 0.5 N 100 N O 1N 25 N 10 N
A traveling wave on a taut string with a tension force T is given by the wave function: y(x,t) = 0.1sin(2rtx-30Ot), where x and y are in meters and t is in seconds. The linear mass density of the string is u = 100 g/m, and the string is 5 m-long. The total energy on the string is O 450 J O 90 J O 45 J O 22.5 J O 225 J im con sts of a 0.8-kg bob connected to a massless
Two waves traveling in the same direction are described by the wave functions: y_1 (x,t)=0.04sin(2+x-6πt+π/2) and y_2 (x,t)=0.04sin(2+x-6πt)where x and y are in meters and t is in seconds. Determine the position x at which y_res=√2 A at t = 1/3 sec. O 1.75 m O 1.25 m O 1.625 m O 1.125 m
A traveling wave on a taut string with a tension force T, is given by the wave function: y(x.t) = 0.05sin(2rtx-100tt), where x and y are in meters and t is in seconds. If the linear mass density of the string is given by µ = 0.01 kg/m, then the tension force on the string is, O 100 N O 10 N O 0.5 N O 1N O 25 N
The equation of a standing wave is y(x,t) = 0.8 cos(0.2Ttx) sin(200rt) %3D where x and y are in cm and t is in seconds. The separation distance between two consecutive nodes is: O 2.5 cm 5 сm 20 cm O 10 cm O 40 cm
A traveling wave on a taut string with a tension force T is given by the wave function: y(x,t) = 0.1sin(2rtx-300t), wherex and y are in meters and t is in seconds. The linear mass density of the string is u = 10 g/m, and the string is 10 m-long. The total energy on the string is 45 J 225 J 90 J 450 J O 22.5 J A simple pendulum is made of a 2 m-string and a bob of mass m. At t = 0. the ion and isgiven an initial velocity y = 0 2 m/s
A standing wave with wavelength A = 1.2 m and frequency f = 80 Hz is generated on a stretched cord. For an element of the cord at x = 0.5 m, the maximum transverse velocity is v(y,max) = 2t m/s. The amplitude A of %3D each of the individual waves producing the standing wave is: