A square loop of wire with edge L and resistance R moves with constant speed v through a uniform magnetic induction confined to a region square whose sides are twice as long as those ofthe square loop (see figure 4). a) Make a graph of the external force F required to move the loop quickly constant as a function of coordinate x, from x = -2L to x = +2L. (The x coordinate is measured from the center of the region of magnetic induction at the center of the loop. is negative when the center of the loop is to the left of the center of the region. Take the positive force to the right.) b) Draw a graph of the current induced in the loop. as a function of x. Take as positive the currents that go counterclockwise. -2L K2L X -L X X X X X B X X X X X 0 Figura 4 X L 2L X
A square loop of wire with edge L and resistance R moves with constant speed v through a uniform magnetic induction confined to a region square whose sides are twice as long as those ofthe square loop (see figure 4). a) Make a graph of the external force F required to move the loop quickly constant as a function of coordinate x, from x = -2L to x = +2L. (The x coordinate is measured from the center of the region of magnetic induction at the center of the loop. is negative when the center of the loop is to the left of the center of the region. Take the positive force to the right.) b) Draw a graph of the current induced in the loop. as a function of x. Take as positive the currents that go counterclockwise. -2L K2L X -L X X X X X B X X X X X 0 Figura 4 X L 2L X
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Transcribed Image Text:A square loop of wire with edge L and resistance R
moves with constant speed v through a uniform
magnetic induction confined to a region square
whose sides are twice as long as those ofthe
square loop (see figure 4).
a) Make a graph of the external force F required to
move the loop quickly constant as a function of
coordinate x, from x = -2L to x = +2L. (The x
coordinate is measured from the center of the
region of magnetic induction at the center of the
loop. is negative when the center of the loop is to
the left of the center of the region. Take the
positive force to the right.)
b) Draw a graph of the current induced in the loop.
as a function of x. Take as positive the currents that
go counterclockwise.
-2L
U
K2L
X
X
X
-L
X
X
X
X
B
X
X
0
Figura 4
X
X
X
X
L
2L
X
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