A square loop of side a carries a current I. Calculate the magnetic field in the center of the loop
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A: Required : The magnetic flux.
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A: Introduction :- Charge q = +qvelocity v→ = vk^magnetic field B→ = Bj^
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A: Introduction: We take elements on the solenoid and write the magnetic field due to it and then we…
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A: Given data: Magnetic field (B) = 1.7 mT = 1.7×10-3 T Current (I) = 26 A Required: The distance (r)
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A: Here number of turns=35 length of the solenoid=6.3cm=6.3×10-2m So number of turns per unit length…
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A: Radius of the circular loop (r) =10 cm =0.1m Current through the loop (I) = 2A
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Q: Suppose you wish to produce a 1-T magnetic field in a toroid with an iron core for which magnetic…
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A: Given: The speed of the proton is 2.5x105 m/s. The strength of the magnetic field is 0.5 T. The…
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