A square loop 24.0 cm on a side has a resistance of 6.10 ΩIt is initially in a 0.665-T magnetic field, with its plane perpendicular to but is removed from the field in 40.0 ms.Calculate the electric energy dissipated in this process. 75. A square loop 24.0 cm on a side has a resistance of 6.10N.It is initially in a 0.665-T magnetic field, with its plane per-pendicular to B, but is removed from the field in 40.0 ms.Calculate the electric energy dissipated in this process.

Magnetic flux is the field lines passing through particular area when that area loop is kept…

A square loop 24.0 cm on a side has a resistance of 6.10 Ω It is initially in a 0.665-T magnetic field, with its plane perpendicular to but is removed from the field in 40.0 ms. Calculate the electric energy dissipated in this process.

A square loop 24.0 cm on a side has a resistance of 6.10 Ω It is initially in a 0.665-T magnetic field, with its plane perpendicular to but is removed from the field in 40.0 ms. Calculate the electric energy dissipated in this process.

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter13: Electromagnetic Induction

Section: Chapter Questions

Problem 26P: A square loop whose sides are 6.0-cm long is made with copper wire of radius 1.0 mm. If a magnetic...

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Question

A square loop 24.0 cm on a side has a resistance of 6.10 Ω
It is initially in a 0.665-T magnetic field, with its plane perpendicular to but is removed from the field in 40.0 ms.
Calculate the electric energy dissipated in this process.

75. A square loop 24.0 cm on a side has a resistance of 6.10N.
It is initially in a 0.665-T magnetic field, with its plane per-
pendicular to B, but is removed from the field in 40.0 ms.
Calculate the electric energy dissipated in this process.

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