### Part 3**Question:**What is the normal component of acceleration when \( t = 15 \, \text{s} \)?**Answer:**\[ a_n = \, \boxed{} \, \text{m/s}^2 \](In this part, students are required to calculate the normal component of acceleration given the time \( t = 15 \, \text{s} \). The answer field is provided for students to input their calculated value in meters per second squared \((\text{m/s}^2)\).) **Title: Understanding Acceleration in Sprinting: A Practical Scenario****Overview:****Scenario:**A sprinter practicing for the 200-meter dash accelerates uniformly from rest at point A and reaches a top speed of 40 km/h at the 53-meter mark. Then, the sprinter maintains this speed for the next 79 meters before uniformly slowing to a final speed of 33 km/h at the finish line. **Objective:**Determine the maximum horizontal acceleration that the sprinter experiences during the run. Identify where this maximum acceleration occurs.**Detailed Diagram Explanation:**The provided diagram illustrates a standard 200-meter track with a focus on the sprinter's path. Key elements in the image include:1. **Track Layout:** - The track is an oval shape commonly used for running events. - There are marked lines indicating the sprinter’s path.2. **Points of Interest:** - **Point A:** The starting point of the sprinter. - **Finish Line:** The endpoint indicating the completion of the 200-meter dash. - There is also a 53-meter mark where the sprinter reaches the top speed of 40 km/h. - There is an additional note indicating a 79-meter segment where the sprinter maintains the top speed.3. **Dimensions:** - A radius of 39.9 meters is marked, indicating the curvature relevant for identifying sections of the track.**Concept Break Down:**1. **Acceleration Phase (0 - 53 meters):** - The sprinter starts from rest. - Reaches a top speed of 40 km/h at the 53-meter mark. - This involves uniform acceleration which can be calculated using kinematic equations.2. **Constant Speed Phase (53 - 132 meters):** - The sprinter maintains a speed of 40 km/h for 79 meters. - No acceleration occurs in this phase.3. **Deceleration Phase (132 - 200 meters):** - The sprinter decelerates uniformly over the last 68 meters. - Final speed at the finish line is 33 km/h. 4. **Maximum Horizontal Acceleration:** - Occurs during the initial acceleration phase (0 - 53 meters). - Calculating this requires kinematic equations to determine the rate of speed increase over time and distance.**Mathematical Analysis:**Use the

Answered: Image /qna-images/answer/37d47829-8c7d-4fc7-9dbc-3e5a88e713d7.jpg

A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 40 km/h at the 53-m mark. He then maintains this speed for the next 79 meters before uniformly slowing to a final speed of 33 km/h at the finish line. Determine the maximum horizontal acceleration which the sprinter experiences during the run. Where does this maximum acceleration value occur? Finish line 39.9 m A

A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 40 km/h at the 53-m mark. He then maintains this speed for the next 79 meters before uniformly slowing to a final speed of 33 km/h at the finish line. Determine the maximum horizontal acceleration which the sprinter experiences during the run. Where does this maximum acceleration value occur? Finish line 39.9 m A

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.

Question

**Title: Understanding Acceleration in Sprinting: A Practical Scenario**

**Overview:**

**Scenario:**

A sprinter practicing for the 200-meter dash accelerates uniformly from rest at point A and reaches a top speed of 40 km/h at the 53-meter mark. Then, the sprinter maintains this speed for the next 79 meters before uniformly slowing to a final speed of 33 km/h at the finish line.

**Objective:**

Determine the maximum horizontal acceleration that the sprinter experiences during the run. Identify where this maximum acceleration occurs.

**Detailed Diagram Explanation:**

The provided diagram illustrates a standard 200-meter track with a focus on the sprinter's path. Key elements in the image include:

1. **Track Layout:**
- The track is an oval shape commonly used for running events.
- There are marked lines indicating the sprinter’s path.

2. **Points of Interest:**
- **Point A:** The starting point of the sprinter.
- **Finish Line:** The endpoint indicating the completion of the 200-meter dash.
- There is also a 53-meter mark where the sprinter reaches the top speed of 40 km/h.
- There is an additional note indicating a 79-meter segment where the sprinter maintains the top speed.

3. **Dimensions:**
- A radius of 39.9 meters is marked, indicating the curvature relevant for identifying sections of the track.

**Concept Break Down:**

1. **Acceleration Phase (0 - 53 meters):**
- The sprinter starts from rest.
- Reaches a top speed of 40 km/h at the 53-meter mark.
- This involves uniform acceleration which can be calculated using kinematic equations.

2. **Constant Speed Phase (53 - 132 meters):**
- The sprinter maintains a speed of 40 km/h for 79 meters.
- No acceleration occurs in this phase.

3. **Deceleration Phase (132 - 200 meters):**
- The sprinter decelerates uniformly over the last 68 meters.
- Final speed at the finish line is 33 km/h.

4. **Maximum Horizontal Acceleration:**
- Occurs during the initial acceleration phase (0 - 53 meters).
- Calculating this requires kinematic equations to determine the rate of speed increase over time and distance.

**Mathematical Analysis:**

Use the

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