A spring with a spring constant of 180N/m is attached to a 1.5kg mass and then set in motion. a. What is the period of this mass-spring system? b. What is the frequency of vibration?
Q: A spring (k = 5.50 x 102 N/m) hangs under the influence of gravity. Affixed to it is a 0.600 g mass.…
A:
Q: A mass of 0.5 kg is attached a vertical spring with a spring constant of k=32 N/m. The mass is…
A: The mass: m=0.5 kg Spring constant: k=32 N/m At time t=0, the position of the mass: x(0)=-0.2 m (The…
Q: A massless spring hangs from the ceiling with a small object attached to its lower end. The object…
A: Part(a)The object oscillates about its equilibrium point, where the spring's upward push and…
Q: I have two springs, one "soft" and easy to stretch, and the other "stiff" and more difficult to…
A: a) Higher the mass , lower the vibration rate, which implies a lower frequency. This is applicable…
Q: Jupiter has an acceleration due to gravity of about 25.m/s². Given this, what would be the period of…
A: The time period of the pendulum can be obtained as T=2πlg
Q: A torsion pendulum is constructed of a copper rod of radius 4mm and length 0.55m is attached to the…
A: Given that a torsion pendulum consisting of a copper rod with radius 4x10-3 m and length 0.55m and a…
Q: A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless…
A: (a)The maximum speed of the block at time T,The position of the block,
Q: A long string attached to a mass M forms a simple pendulum. The string, however, is weak enough so…
A: The string will break when the tension on the string will be maximum. From the free body diagram of…
Q: A 800 g air-track glider attached to a spring with spring constant 10 N/m is sitting at rest on a…
A: Given data: Mass of air track glider attached to the spring is m1=0.8 kg Mass of another glider is…
Q: A 0.5 kg block is attached to a string (k = 12.5 N/m), the damped frequency is 0.2 % lower than the…
A:
Q: A manufacturer need to determine the spring constant of a brand new set of supposedly identical…
A:
Q: A mountain climber, who has had physics in high school, figures out gravity at his location in the…
A: (a) Period of the pendulum T=2πlgg=4π2lT2=4π2400 cm1.39×10-3 h21 h3600 s21 m102 cm=6.306 m/s2≈6.31…
Q: A particle of mass 100 g undergoes a simple harmonic motion. The restoring force is provided by a…
A: Answer is Option (c) The expression for find period of oscillation is T=2πmk
Q: A mass on a string of unknown length oscillates as a pendulum with a period of 5.0 ss. Parts B to D…
A: Given, time period of pendulum= 5 sec. we need to calculate, B. What is the period if the string…
Q: A block of mass 1.37 kg is connected to a spring of spring constant 136 N/m which is then set into…
A: Given Mass (m) = 1.37 kg Spring constant (k) = 136…
Q: A mass m = 3.2 kg is at the end of a horizontal spring of spring constant k = 325 N/m on a…
A:
Q: 4 0.5 /1.5 2 -4
A:
Q: 1. Consider a damped spring-mass system with m = 1kg, k = 4 kg/s^2 and b = 5 kg/s. a. Write the…
A: Given: The mass of the object is m = 1 kg The value of the spring constant is k = 4 kg s-2 The…
Q: A mass M is attached to an ideal massless spring. When this system is et in motion with amplitude A,…
A:
Q: A mass of 2.00kg is pulled to the right 15.5 cm and released at t=0 seconds. The period of the…
A: Given data: Mass m=2.00 kg. Initial position x∘=15.5 cm. Time period of oscillation T=2.05 s. At…
Q: 2. A 0.85kg block on a spring is oscillating with an amplitude of A = 0.42m and a frequency of f =…
A: The mass of the block is 0.85 kg. The amplitude of the oscillation is 0.42 m. The frequency of the…
Q: 2. An object attached to a coiled spring is pushed up a distance 6 inches from its rest position and…
A:
Q: 2. A 0.85kg block on a spring is oscillating with an amplitude of A = 0.42m and a frequency of f =…
A: Given data: Mass of the block, m=0.85 kg Amplitude of the block, A=0.42 m Frequency of oscillation,…
Q: A spring with spring constant k hangs vertically. Fermina hangs a mass from the spring and displaces…
A:
Q: A mass-spring system has a solution of x = 0.5 m sin (57/12*t). A. The system's amplitude is m. B.…
A: Hey, there are multiple subparts posted, we are authorized to answer three subparts at a time, since…
Q: N10T.4 Aglider on an air track is connected by a spring to the end of the air track. If it takes…
A: The frequency of the vibration of the spring is,
Q: For a simple pendulum, why must the pendulum's oscillations be small in order for the pendulum's…
A:
Q: A 4.5-kg block is hung from a spring causing the spring to elongate 12 cm. a. What is the spring…
A: a) in equilibrium spring force = gravitational force k x = mg k = mg/x k = 367.5 N/m
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
- 1. A large simple pendulum is 2 m long. The mass at the end is 3 kg. a. What is the period of oscillation? b. The length of the pendulum is doubled to 4 m. What is the period of oscillation? C. The length of the pendulum is shortened back to 2 m, but the mass is doubled to 6 kg. What is the period of oscillation?Part2An ideal rubber ball bouncing vertically on a hard floor does not lose mechanical energy. This motion is NOT simple harmonic; all of the following are reasons for this EXCEPT A. The period of the motion depends on the amplitude. B. The force on the ball is not proportional to displacement. C. The gravitational force is the force trying to restore equilibrium. D. The equilibrium position is not at the midpoint of the oscillation.
- A 170 g mass attached to a horizontal spring oscillates at a frequency of 4.60 Hz. At t = 0 s, the mass is at x = 5.80 cm and has vx = -38.0 cm/s. A. Determine the total energy. B. Determine the position at t = 3.40 s.A 150 g mass is hung from a massless vertical spring, causing the spring to stretch by 10 cm and come to rest. The mass is then displaced from its equilibrium position by 5 cm and released. (g=9.8 m/s/s) a. What is the period of the resultant motion? b. What is the maximum speed of the mass during its motion?A 2.2 kg mass oscillating while attached to a vertical spring with spring constant k = 11 N/m travels through its equilibrium position at speed v = 1.1 m/s. What is the amplitude of this oscillator's motion? A. 0.22 m B. 0.49 m C. 0.40 m D. 0.58 m O A OB oo O C D
- A mass hanging from a spring undergoes vertical simple harmonic motion.a. Where in the motion is the magnitude of the net force equal to zero?b. Where in the motion is the velocity equal to zero?c. Where in the motion does the acceleration have its greatest magnitude?d. Where in the motion is the spring force equal to zero?a. If you took a pendulum to the moon where g = 1.6 m/s2, what change would you observe in its period? b. Are there factors other than length and gravitational acceleration that affect the period of the pendulum? Why is the period of a pendulum bob independent of its mass?A 1.0 kg block is attached to a spring with spring constant 16 N/m. While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 40 cm/s.What area. The amplitude of the subsequent oscillations?b. The block’s speed at the point where x = 1/2 A?
- A mass of 2.00kg is pulled to the right 15.5 cm and released at t=0 seconds. The period of the oscillation on a frictionless surface is measured to be 2.05 seconds. a. what is the spring constent? b. what is the maximum velocity? c. what is the maximum acceleration?A 0.250 kg block oscillates on a spring horizontally on a frictionless surface. The spring has a spring constant of 200 N/m. If the amplitude of the oscillations is 24.5 cm, then what is the maximum speed of the block?a. 0.060 m/s.b. 0.17 m/s.c. 0.24 m/s.d. 6.9 m/s.e. 4.9 m/s.B6 The amplitude as a function of time for a mass-spring system with damping is given by A(t) = 0.25e-0.2t, where all quantities are in S.I. units. The mass is 1.0 kg, and the spring constant is 0.42 N/m. Which of the following is/are TRUE about the system? The system amplitude decays. The system experiences an underdamped motion. The damping constant of the system is 0.4 N/s. A B с