3) A spring mechanism launches a skateboarder horizontally, as shown. Neglect friction for this problem.C (max)اللہkAxFapPEsp (1)KE(I)VA옷...PEsp (A) =KE(A)N.a) When compressed, what force must be applied to the spring, and what is the force from the springHow much work must be done to compress the spring? Include the signs for each.VA =J.FspJ.J.m/sPE(1) :VBb) When the spring is compressed, before the person is launched, what are each of the followingThese are the initial (I) values, and you should get numbers for each of these.Etot (1)BN.PEg (A) =Etot (A)hgWc) When the spring is released, what are each of the following when the person is at point ASome of these will be in terms of variables.J.m = 38 kgd) Using conservation of energy, determine the speed of the person at A?k = 1750 N/mAx= -1.5 mJ.hBcompress= 1 mJ.J. When the person leaves the top of the ramp, (vertically, hg = 1m), what are each of the followingSome of these will be in terms of variables.PE (B) =KE(B)VB =PEsp (C) =KE(C)=f) Using conservation of energy, determine the speed of the person at B (the top of the ramp)?bmax =m/sg) When the person is at point C, the maximum height (hmax), what are each of the following?Some of these will be in terms of variables.Wg =JJJ.J.m.P/E (B)Etot (B)PE (C) =Erot (C):h) Using conservation of energy, determine the maximum height the person will reach?J.=J.i) Find the work done by gravity (including the sign) as the skater goes up to point C.

Name: 3) A spring mechanism launches a skateboarder horizontally, as shown.
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: 3) A spring mechanism launches a skateboarder horizontally, as shown. Neglect friction for this problem.C (max)اللہkAxFapPEsp (1)KE(I)VA옷...PEsp (A) =KE(A)N.a) When compressed, what force must be applied to the spring, and what is the force from the