A spring has natural length 26 cm. Compare the work (in J) W₁ done in stretching the spring from 26 cm to 36 cm with the work (in J) W₂ done in stretching it from 36 cm to 46 cm. (Use k for the spring constant.) W₁ = W₂ = J How are W₂ and W₁ related? W₂ = W₁

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I am currently in Calculus II working on work problems and stuck on this spring problem attached. I have set up the two distinct work integrals but stuck on how I need to find the Joules. I also have attached my work.

2
50
54/12 - 05K
लगन
=
[]=
[dox -&D+<[27] <= ६ = "
2'
2
Q= 712201
2-डी/x
30-=-xxf="M
पत्र
103
21
DSK CSK =0
05KE.USK
bh
15=5
Satyl=pl
2
(2.) 371 = (2)/71
ऊँ)
2
[+ z] [suutth-252-250/-
1501
Wr
7
D
()
SM
36-26:10
10
2
.2
Kide -> [= "/" ² → K(2)² KCL)²
uz= ? (J) sf kide-> 10/2
Kedes + > KIDS K(4)
36-46
30-26- 10-2.1M.
24-36
15 SPRING NATURAR LENGTH = 26cm
04 = 22-24
0
1/ ²7²7 <- xxx 5 < (1) ; = 'm
Transcribed Image Text:2 50 54/12 - 05K लगन = []= [dox -&D+<[27] <= ६ = " 2' 2 Q= 712201 2-डी/x 30-=-xxf="M पत्र 103 21 DSK CSK =0 05KE.USK bh 15=5 Satyl=pl 2 (2.) 371 = (2)/71 ऊँ) 2 [+ z] [suutth-252-250/- 1501 Wr 7 D () SM 36-26:10 10 2 .2 Kide -> [= "/" ² → K(2)² KCL)² uz= ? (J) sf kide-> 10/2 Kedes + > KIDS K(4) 36-46 30-26- 10-2.1M. 24-36 15 SPRING NATURAR LENGTH = 26cm 04 = 22-24 0 1/ ²7²7 <- xxx 5 < (1) ; = 'm
A spring has natural length 26 cm. Compare the work (in J) W₁ done in stretching the spring from 26 cm to 36 cm with the work (in J) W₂ done in stretching it from 36 cm to 46 cm. (Use k
for the spring constant.)
W₁
W₂
=
=
J
=
J
How are W₂ and W₁ related?
W 2
1
Transcribed Image Text:A spring has natural length 26 cm. Compare the work (in J) W₁ done in stretching the spring from 26 cm to 36 cm with the work (in J) W₂ done in stretching it from 36 cm to 46 cm. (Use k for the spring constant.) W₁ W₂ = = J = J How are W₂ and W₁ related? W 2 1
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