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A spinless particle in a box of mass m moving in an infinite potential well of length 2L, with walls at x 0 and x = 2L. Using first-order perturbation theory, calculate the correction to the energy of the nth excited state if it is modified at the bottom by the following perturbation aVod(x-L), where à < 1 Given that the unperturbed solutions are: wulw) = sin () En n². Wn(x): Sm L 2L AVo/L for n odd, 2AVo/T for n even AVo/L for n even, 2AVo/T for n odd 2AVo/T for n odd, zero for n even 2AV0/T for n even, zero for n odd O AVo/L for n even, zero for n odd O AVo/L for n odd, zero forn even

A spinless particle in a box of mass m moving in an infinite potential well of length 2L, with walls at x 0 and x = 2L. Using first-order perturbation theory, calculate the correction to the energy of the nth excited state if it is modified at the bottom by the following perturbation aVod(x-L), where à < 1 Given that the unperturbed solutions are: wulw) = sin () En n². Wn(x): Sm L 2L AVo/L for n odd, 2AVo/T for n even AVo/L for n even, 2AVo/T for n odd 2AVo/T for n odd, zero for n even 2AV0/T for n even, zero for n odd O AVo/L for n even, zero for n odd O AVo/L for n odd, zero forn even

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A spinless particle in a box of mass m moving in an infinite potential well of length 2L, with walls at x 0 and x = 2L. Using first-order perturbation theory, calculate the correction to the energy of the nth excited state if it is modified at the bottom by the following perturbation iVod(x - L), where i « 1 Given that the unperturbed solutions are: En n². sin 2L Wn(x) = %3D SmL2 O AVo/L for n odd, 2AVo/T for n even O AVo/L for n even, 2AVo/T for n odd 2AVo/T for n odd, zero for n even O 2AVo/T for n even, zero for n odd O AVo/L for n even , zero for n odd O AVo/L for n odd, zero for n even
Transcribed Image Text:A spinless particle in a box of mass m moving in an infinite potential well of length 2L, with walls at x 0 and x = 2L. Using first-order perturbation theory, calculate the correction to the energy of the nth excited state if it is modified at the bottom by the following perturbation iVod(x - L), where i « 1 Given that the unperturbed solutions are: En n². sin 2L Wn(x) = %3D SmL2 O AVo/L for n odd, 2AVo/T for n even O AVo/L for n even, 2AVo/T for n odd 2AVo/T for n odd, zero for n even O 2AVo/T for n even, zero for n odd O AVo/L for n even , zero for n odd O AVo/L for n odd, zero for n even
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