13- A spherical raindrop 2.9 mm in diameter falls through a vertical distance of 4050 m. Take the cross-sectional area of a raindrop = ar², drag coefficient = 0.45, density of water to be1000 kg/m3, and density of air to be 1.2 kg/m3.(a) Calculate the speed (in m/s) a spherical raindrop would achieve falling from 4050 m in the absence of air drag.m/s(b) What would its speed (in m/s) be at the end of 4050 m when there is air drag?m/s

a) The required speed is, v=gt =g2sg =9.8240509.8 =281.74 m/s b) The mass is, m=ρV =ρwater43πr3 =100043π2.9×10-323 =1.277×10-5 kg Thus, the required terminal velocity is, vt=2mgCρairA =21.277×10-59.80.451.2π2.9×10-322 =8.38 m/s

Science

Advanced Physics

A spherical raindrop 2.9 mm in diameter falls through a vertical distance of 4050 m. Take the cross-sectional area of a raindrop = tr“, drag coefficient = 0.45, density of water to be 1000 kg/m3, and density of air to be 1.2 kg/m³. (a) Calculate the speed (in m/s) a spherical raindrop would achieve falling from 4050 m in the absence of air drag. m/s (b) What would its speed (in m/s) be at the end of 4050 m when there is air drag? m/s

A spherical raindrop 2.9 mm in diameter falls through a vertical distance of 4050 m. Take the cross-sectional area of a raindrop = tr“, drag coefficient = 0.45, density of water to be 1000 kg/m3, and density of air to be 1.2 kg/m³. (a) Calculate the speed (in m/s) a spherical raindrop would achieve falling from 4050 m in the absence of air drag. m/s (b) What would its speed (in m/s) be at the end of 4050 m when there is air drag? m/s