A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displaced2R?g(es - P), where R is the radius of the sphere, ps9nfluid, while the drag force is assumed to be given by Stokes' law, Fs = 6xrnv. The terminal speed is given by v =is its density, andP1is thedensity of the fluid, and n the coefficient of viscosity.Using the equation above, find the viscosity of motor oil (in mPa · s) in which a steel ball of radius 0.9 mm falls with a terminal speed of 6.16 cm/s. The densities of the ball and the oil are 7.86 and0.88 g/mL, respectively.mPa • s

Given Data, Radius of the ball (R)=0.9 mm Terminal velocity(v)=6.16 m/s Density o the ball (ρs)=7.86…

A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displace 2R?g, (e- P), where R is the radius of the sphere, p, is its density, and p, is the 9n fluid, while the drag force is assumed to be given by Stokes' law, Fs = 6arnv. The terminal speed is given by v = density of the fluid, and 7 the coefficient of viscosity. Using the equation above, find the viscosity of motor oil (in mPa - s) in which a steel ball of radius 0.9 mm falls with a terminal speed of 6.16 cm/s. The densities of the ball and the oil are 7.86 and 0.88 g/mL, respectively. mPa -s

A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displace 2R?g, (e- P), where R is the radius of the sphere, p, is its density, and p, is the 9n fluid, while the drag force is assumed to be given by Stokes' law, Fs = 6arnv. The terminal speed is given by v = density of the fluid, and 7 the coefficient of viscosity. Using the equation above, find the viscosity of motor oil (in mPa - s) in which a steel ball of radius 0.9 mm falls with a terminal speed of 6.16 cm/s. The densities of the ball and the oil are 7.86 and 0.88 g/mL, respectively. mPa -s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displaced
2R?g
(es - P), where R is the radius of the sphere, ps
9n
fluid, while the drag force is assumed to be given by Stokes' law, Fs = 6xrnv. The terminal speed is given by v =
is its density, and
P1
is the
density of the fluid, and n the coefficient of viscosity.
Using the equation above, find the viscosity of motor oil (in mPa · s) in which a steel ball of radius 0.9 mm falls with a terminal speed of 6.16 cm/s. The densities of the ball and the oil are 7.86 and
0.88 g/mL, respectively.
mPa • s

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