A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displace 2R?g, (e- P), where R is the radius of the sphere, p, is its density, and p, is the 9n fluid, while the drag force is assumed to be given by Stokes' law, Fs = 6arnv. The terminal speed is given by v = density of the fluid, and 7 the coefficient of viscosity. Using the equation above, find the viscosity of motor oil (in mPa - s) in which a steel ball of radius 0.9 mm falls with a terminal speed of 6.16 cm/s. The densities of the ball and the oil are 7.86 and 0.88 g/mL, respectively. mPa -s
A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displace 2R?g, (e- P), where R is the radius of the sphere, p, is its density, and p, is the 9n fluid, while the drag force is assumed to be given by Stokes' law, Fs = 6arnv. The terminal speed is given by v = density of the fluid, and 7 the coefficient of viscosity. Using the equation above, find the viscosity of motor oil (in mPa - s) in which a steel ball of radius 0.9 mm falls with a terminal speed of 6.16 cm/s. The densities of the ball and the oil are 7.86 and 0.88 g/mL, respectively. mPa -s
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter12: Fluid Dynamics And Its Biological And Medical Applications
Section: Chapter Questions
Problem 38PE: A spherical particle falling at a terminal speed in a liquid must have the gravitational force...
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![A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displaced
2R?g
(es - P), where R is the radius of the sphere, ps
9n
fluid, while the drag force is assumed to be given by Stokes' law, Fs = 6xrnv. The terminal speed is given by v =
is its density, and
P1
is the
density of the fluid, and n the coefficient of viscosity.
Using the equation above, find the viscosity of motor oil (in mPa · s) in which a steel ball of radius 0.9 mm falls with a terminal speed of 6.16 cm/s. The densities of the ball and the oil are 7.86 and
0.88 g/mL, respectively.
mPa • s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2f2d422d-c976-44f1-b274-3184de567805%2F53a3f062-d424-4a70-aaaa-05976af37047%2Fhg7sa2vv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displaced
2R?g
(es - P), where R is the radius of the sphere, ps
9n
fluid, while the drag force is assumed to be given by Stokes' law, Fs = 6xrnv. The terminal speed is given by v =
is its density, and
P1
is the
density of the fluid, and n the coefficient of viscosity.
Using the equation above, find the viscosity of motor oil (in mPa · s) in which a steel ball of radius 0.9 mm falls with a terminal speed of 6.16 cm/s. The densities of the ball and the oil are 7.86 and
0.88 g/mL, respectively.
mPa • s
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