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A sphere A of mass m=2 kg is released from rest in the position shown and strikes the frictionless inclined surface of a wedge B of mass mg= 6 kg with a velocity v,= 3 m/s. The wedge, which is supported by rollers and may move freely in the horizontal direction, is initially at rest. Knowing that 0 = 30° and that the coefficient of restitution between the sphere and the wedge is e = 0.80, determine the velocities of the sphere and of the wedge immediately after the impact. en V とt V。e。 = \isê - 26en ニ VAO ニ VAO NAI Ve。こ В 1こ BI こ 30° = - o-866 V81 ee -0.SVBien

A sphere A of mass m=2 kg is released from rest in the position shown and strikes the frictionless inclined surface of a wedge B of mass mg= 6 kg with a velocity v,= 3 m/s. The wedge, which is supported by rollers and may move freely in the horizontal direction, is initially at rest. Knowing that 0 = 30° and that the coefficient of restitution between the sphere and the wedge is e = 0.80, determine the velocities of the sphere and of the wedge immediately after the impact. en V とt V。e。 = \isê - 26en ニ VAO ニ VAO NAI Ve。こ В 1こ BI こ 30° = - o-866 V81 ee -0.SVBien

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Do not solve the full qn

My question is why is the vector VAot = 1.5 and VAon =-2.6 as shown in the solution. I understand VAot is = -3cos30=-1.5 and VAon = -3sin30 =-2.6 

Why is it postive 1.5 instead of negative 1.5 or for VAon why isit negative 2.6 and not positive 2.6?

Why is Vb1t = -0.866 and not 0.866 and Vb1n = -0.5 and not 0.5. I dont get it how to visualise the vector direction.

Please provide your answer by drawing a vector diagram with the angles to illustrate it.

4. A sphere A of mass m= 2 kg is released from rest in the position shown and strikes the frictionless inclined surface of a wedge B of mass m3= 6 kg with a velocity v,= 3 m/s. The wedge, which is supported by rollers and may move freely in the horizontal direction, is initially at rest. Knowing that 0 = 30° and that the coefficient of restitution between the sphere and the wedge is e = 0.80, determine the velocities of the sphere and of the wedge immediately after the impact. A en へ 3ミ - + è. = usá-262, こ NAO ex AD VAO NAI Vo こ В VBi et + V81 30° こ BI -o.866 V8l ex - 0.S Ver en it VA」こ Va くク く。
Transcribed Image Text:4. A sphere A of mass m= 2 kg is released from rest in the position shown and strikes the frictionless inclined surface of a wedge B of mass m3= 6 kg with a velocity v,= 3 m/s. The wedge, which is supported by rollers and may move freely in the horizontal direction, is initially at rest. Knowing that 0 = 30° and that the coefficient of restitution between the sphere and the wedge is e = 0.80, determine the velocities of the sphere and of the wedge immediately after the impact. A en へ 3ミ - + è. = usá-262, こ NAO ex AD VAO NAI Vo こ В VBi et + V81 30° こ BI -o.866 V8l ex - 0.S Ver en it VA」こ Va くク く。
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