A sphere A of mass m=2 kg is released from rest in the position shown and strikes the frictionless inclined surface of a wedge B of mass mg= 6 kg with a velocity v,= 3 m/s. The wedge, which is supported by rollers and may move freely in the horizontal direction, is initially at rest. Knowing that 0 = 30° and that the coefficient of restitution between the sphere and the wedge is e = 0.80, determine the velocities of the sphere and of the wedge immediately after the impact. en V とt V。e。 = \isê - 26en ニ VAO ニ VAO NAI Ve。こ В 1こ BI こ 30° = - o-866 V81 ee -0.SVBien
A sphere A of mass m=2 kg is released from rest in the position shown and strikes the frictionless inclined surface of a wedge B of mass mg= 6 kg with a velocity v,= 3 m/s. The wedge, which is supported by rollers and may move freely in the horizontal direction, is initially at rest. Knowing that 0 = 30° and that the coefficient of restitution between the sphere and the wedge is e = 0.80, determine the velocities of the sphere and of the wedge immediately after the impact. en V とt V。e。 = \isê - 26en ニ VAO ニ VAO NAI Ve。こ В 1こ BI こ 30° = - o-866 V81 ee -0.SVBien
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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My question is why is the vector VAot = 1.5 and VAon =-2.6 as shown in the solution. I understand VAot is = -3cos30=-1.5 and VAon = -3sin30 =-2.6
Why is it postive 1.5 instead of negative 1.5 or for VAon why isit negative 2.6 and not positive 2.6?
Why is Vb1t = -0.866 and not 0.866 and Vb1n = -0.5 and not 0.5. I dont get it how to visualise the vector direction.
Please provide your answer by drawing a vector diagram with the angles to illustrate it.
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