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A speedboat moves west at 108 km/h for 26.0 min. It then moves at 60.0° south of west at 90.0 km/h for 10.0 min. What is the average speed for the trip? km/h

A speedboat moves west at 108 km/h for 26.0 min. It then moves at 60.0° south of west at 90.0 km/h for 10.0 min. What is the average speed for the trip? km/h

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Required Information A speedboat moves west at 108 km/h for 26.0 minutes. It then moves at 60.0° south of west at 90.0 km/h for 10.0 minutes. **Question:** What is the average speed for the trip? □ km/h --- **Explanation:** To calculate the average speed, we need to determine the total distance traveled by the speedboat and the total time taken for the trip. 1. **Distance Calculation:** - **First Leg (Westward):** - Speed: 108 km/h - Time: 26.0 minutes = 26.0/60 hours - Distance = Speed × Time - **Second Leg (60.0° South of West):** - Speed: 90.0 km/h - Time: 10.0 minutes = 10.0/60 hours - Distance = Speed × Time 2. **Add Both Distances** to get the total distance traveled. 3. **Total Time** is the sum of the time of both legs of the trip. 4. **Average Speed Calculation:** - Average Speed = Total Distance / Total Time By following the steps above, you can find the average speed of the speedboat for the entire journey.
Transcribed Image Text:### Required Information A speedboat moves west at 108 km/h for 26.0 minutes. It then moves at 60.0° south of west at 90.0 km/h for 10.0 minutes. **Question:** What is the average speed for the trip? □ km/h --- **Explanation:** To calculate the average speed, we need to determine the total distance traveled by the speedboat and the total time taken for the trip. 1. **Distance Calculation:** - **First Leg (Westward):** - Speed: 108 km/h - Time: 26.0 minutes = 26.0/60 hours - Distance = Speed × Time - **Second Leg (60.0° South of West):** - Speed: 90.0 km/h - Time: 10.0 minutes = 10.0/60 hours - Distance = Speed × Time 2. **Add Both Distances** to get the total distance traveled. 3. **Total Time** is the sum of the time of both legs of the trip. 4. **Average Speed Calculation:** - Average Speed = Total Distance / Total Time By following the steps above, you can find the average speed of the speedboat for the entire journey.
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