A spectroscope breaks electromagnetic radiation up into its constituent parts. This can be accomplished with refraction and with diffraction. Explain how astronomers can use the spectrum to determine the temperature of the object that produced the electromagnetic radiation.
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A spectroscope breaks
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- As you may well know, placing metal objects inside a microwave oven can generate sparks. Two of your friends are arguing over the cause of the sparking, with one stating that the microwaves "herd" electrons into "pointy" areas of the metal object, from which the electrons jump from one part of the object to another. The other friend says that the sparks are caused by the photoelectric effect. Prove or disprove the latter idea using basic physics. Suppose the typical work function of the metal is roughly 3.630 × 10-19 J. Calculate the maximum wavelength in angstroms of the radiation that will eject electrons from the metal. wavelength: Å4. In an experiment on the photoelectric effect, a metal is illuminated by visible light of different wavelengths. A photoelectron has a maximum kinetic energy of 0.9 eV when red light of wavelength 640 nm is used. With blue light of wavelength 420 nm, the maximum kinetic energy of the photoelectron is 1.9 eV. Use this information to calculate an experimental value for the Planck constant h. [Explain why different elements produce different spectral absorption and emission lines. Calculate the wavelength of a photon that has an energy of 4.96 eV. (Hint: h*c {Planck's constant * the speed of light }= 1240 eV*nm;) What type of radiation/light (from the electromagnetic spectrum) is the photon from the previous question? Why is it that radio telescopes need to be so large or organized in arrays? this is all one question with different parts. Thank you.
- Calculate the maximum wavelength, Amax, of electromagnetic radiation that could eject electrons from the surface of copper, which has a work function of 7.26 x 10-1⁹ J. Amax = λ = m If the maximum speed of the emitted photoelectrons is 4.92 x 106 m/s, what wavelength of electromagnetic radiation struck the surface and caused the ejection of the photoelectrons? mMetro by T-Mobile Light that has a frequency of about 5.20 x 1014 Hz (a wavelength of about 578 nm energy in joules of the photons associated with this light? Need Help? Read It [-/2 Points] Need Help? Photons of a certain ultraviolet light have an energy of 6.34 × 10-1⁹ J. (a) What is the frequency of this UV light? Hz [-/2 Points] (b) Use λ = c/f to calculate its wavelength in nanometers (nm). nm DETAILS Need Help? Submit Answer MY NOTES [1/1 Points] Read It webassign.net DETAILS Photons of a certain infrared light have an energy of 1.78 x 10-1⁹ J. (a) What is the frequency of this IR light? Hz SHIPPS14 9.E.003. MY NOTES (b) Use λ = c/f to calculate its wavelength in nanometers. nm Read It DETAILS SHIPPS14 9.E.004. MY NOTES PREVIOUS ANSWERS ASK YOUR TEACHER ASK YO PRACTICE ANOTHER ASK YO SHIPPS14 9.E.005.How fast must an electron be moving if all its kinetic energy is lost to a single x-ray photon with the following characteristics? (a) The photon has a wavelength of 3.55 x 10-8 m near the high end of the x-ray electromagnetic spectrum. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.c (b) The photon has a wavelength of 3.55 x 10-13 m near the low end of the x-ray electromagnetic spectrum,
- What is the energy of an ultraviolet photon with wave- length 139 nm?When John broke his arm, the doctor took an x-ray of John’s arm. John had never seen an x-ray before. He asked the doctor how the x-ray was able to show his bones but not his skin and other tissue. Which explanation would the doctor best provide to John? A X-rays have lower energy than visible light and therefore produce a black background behind the bone image. B X-rays have lower frequency than infrared light and therefore penetrates through the bone. C X-rays have higher frequency than gamma rays and therefore pass through skin and bone. D X-rays have higher frequency than visible light and therefore can pass through skin and tissue but not through the bone.