A specific steroid has a Amax of 251 nm and a molar absorptivity e of 11, 500 L mol-¹ cm-¹. What is the concentration of the compound in a solution whose absorbance at 251 nm is A = 0.075 with a sample pathlength of 1.00 cm? concentration: M
A specific steroid has a Amax of 251 nm and a molar absorptivity e of 11, 500 L mol-¹ cm-¹. What is the concentration of the compound in a solution whose absorbance at 251 nm is A = 0.075 with a sample pathlength of 1.00 cm? concentration: M
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A specific steroid has a λ<sub>max</sub> of 251 nm and a molar absorptivity ε of 11,500 L mol<sup>−1</sup> cm<sup>−1</sup>. What is the concentration of the compound in a solution whose absorbance at 251 nm is A = 0.075 with a sample pathlength of 1.00 cm?
**Concentration:** [Textbox] M
### Explanation:
This problem relates to the application of Beer-Lambert Law in determining the concentration of a compound in a solution. The Beer-Lambert Law is expressed as:
\[ A = \varepsilon \cdot c \cdot l \]
Where:
- \( A \) is the absorbance.
- \( \varepsilon \) is the molar absorptivity (in L mol<sup>−1</sup> cm<sup>−1</sup>).
- \( c \) is the concentration of the solution (in mol L<sup>−1</sup>).
- \( l \) is the path length of the sample cell (in cm).
In this scenario:
- The maximum wavelength \( λ<sub>max</sub> \) is 251 nm.
- The molar absorptivity \( \varepsilon \) is 11,500 L mol<sup>−1</sup> cm<sup>−1</sup>.
- The absorbance \( A \) is 0.075.
- The path length \( l \) is 1.00 cm.
To find the concentration \( c \), rearrange the equation:
\[ c = \frac{A}{\varepsilon \cdot l} \]
Substituting the known values will yield the concentration.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2f591c64-216a-4120-ac44-1b23dfa641af%2F57fa69ea-2a8c-4677-ab2d-fdabec2092c8%2F4pnfqzh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A specific steroid has a λ<sub>max</sub> of 251 nm and a molar absorptivity ε of 11,500 L mol<sup>−1</sup> cm<sup>−1</sup>. What is the concentration of the compound in a solution whose absorbance at 251 nm is A = 0.075 with a sample pathlength of 1.00 cm?
**Concentration:** [Textbox] M
### Explanation:
This problem relates to the application of Beer-Lambert Law in determining the concentration of a compound in a solution. The Beer-Lambert Law is expressed as:
\[ A = \varepsilon \cdot c \cdot l \]
Where:
- \( A \) is the absorbance.
- \( \varepsilon \) is the molar absorptivity (in L mol<sup>−1</sup> cm<sup>−1</sup>).
- \( c \) is the concentration of the solution (in mol L<sup>−1</sup>).
- \( l \) is the path length of the sample cell (in cm).
In this scenario:
- The maximum wavelength \( λ<sub>max</sub> \) is 251 nm.
- The molar absorptivity \( \varepsilon \) is 11,500 L mol<sup>−1</sup> cm<sup>−1</sup>.
- The absorbance \( A \) is 0.075.
- The path length \( l \) is 1.00 cm.
To find the concentration \( c \), rearrange the equation:
\[ c = \frac{A}{\varepsilon \cdot l} \]
Substituting the known values will yield the concentration.
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