A spaceship's orbital maneuver requires a speed increase of 1.00 x 103 m/s. If its engine has an exhaust speed of 2.90 × 103 m/s, determine the required ratio ". of its initial mass to its final mass. (The difference m, - M, Mf equals the mass of the ejected fuel.)

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**Problem Statement:**

A spaceship's orbital maneuver requires a speed increase of \( 1.00 \times 10^3 \) m/s. If its engine has an exhaust speed of \( 2.90 \times 10^3 \) m/s, determine the required ratio \( \frac{M_i}{M_f} \) of its initial mass to its final mass. (The difference \( M_i - M_f \) equals the mass of the ejected fuel.)

**Explanation and Solution:**

To solve this problem, we need to use the Tsiolkovsky rocket equation (also known as the ideal rocket equation), which relates the initial and final masses of a rocket to the velocity change and exhaust velocity. The equation is:

\[
\Delta v = v_e \ln \left( \frac{M_i}{M_f} \right)
\]

Where:
- \(\Delta v\) is the change in velocity (speed increase) required.
- \(v_e\) is the exhaust velocity.
- \(M_i\) is the initial mass of the spaceship.
- \(M_f\) is the final mass of the spaceship.
- \(\ln\) denotes the natural logarithm.

Given data:
- \(\Delta v = 1.00 \times 10^3 \text{ m/s}\)
- \(v_e = 2.90 \times 10^3 \text{ m/s}\)

Step 1: Rearrange the Tsiolkovsky rocket equation to solve for \( \frac{M_i}{M_f} \):

\[
\frac{M_i}{M_f} = e^{\frac{\Delta v}{v_e}}
\]

Step 2: Substitute the given values into the equation:

\[
\frac{M_i}{M_f} = e^{\frac{1.00 \times 10^3 \text{ m/s}}{2.90 \times 10^3 \text{ m/s}}}
\]

Step 3: Calculate the exponent:

\[
\frac{1.00 \times 10^3}{2.90 \times 10^3} = \frac{1}{2.9} \approx 0.3448
\]

Step 4: Use the exponential function:

\[
\frac{M_i}{M_f} = e^{0.3448} \approx
Transcribed Image Text:**Problem Statement:** A spaceship's orbital maneuver requires a speed increase of \( 1.00 \times 10^3 \) m/s. If its engine has an exhaust speed of \( 2.90 \times 10^3 \) m/s, determine the required ratio \( \frac{M_i}{M_f} \) of its initial mass to its final mass. (The difference \( M_i - M_f \) equals the mass of the ejected fuel.) **Explanation and Solution:** To solve this problem, we need to use the Tsiolkovsky rocket equation (also known as the ideal rocket equation), which relates the initial and final masses of a rocket to the velocity change and exhaust velocity. The equation is: \[ \Delta v = v_e \ln \left( \frac{M_i}{M_f} \right) \] Where: - \(\Delta v\) is the change in velocity (speed increase) required. - \(v_e\) is the exhaust velocity. - \(M_i\) is the initial mass of the spaceship. - \(M_f\) is the final mass of the spaceship. - \(\ln\) denotes the natural logarithm. Given data: - \(\Delta v = 1.00 \times 10^3 \text{ m/s}\) - \(v_e = 2.90 \times 10^3 \text{ m/s}\) Step 1: Rearrange the Tsiolkovsky rocket equation to solve for \( \frac{M_i}{M_f} \): \[ \frac{M_i}{M_f} = e^{\frac{\Delta v}{v_e}} \] Step 2: Substitute the given values into the equation: \[ \frac{M_i}{M_f} = e^{\frac{1.00 \times 10^3 \text{ m/s}}{2.90 \times 10^3 \text{ m/s}}} \] Step 3: Calculate the exponent: \[ \frac{1.00 \times 10^3}{2.90 \times 10^3} = \frac{1}{2.9} \approx 0.3448 \] Step 4: Use the exponential function: \[ \frac{M_i}{M_f} = e^{0.3448} \approx
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