A spaceship is moving in a vertical line. Its velocity at time (t) is given by v(t)=3(t)^2 +2(t)   (a) How far has the spaceship progressed over time (t) interval [0,3]? (b) Let y(t) denote the position of the spaceship at time t. Find y(t) if y(0) = 1/10 . (c) What is the average height of the spaceship over the interval between t = 1 and t = 3 hours

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A spaceship is moving in a vertical line. Its velocity at time (t) is given by v(t)=3(t)^2 +2(t)

 

(a) How far has the spaceship progressed over time (t) interval [0,3]?


(b) Let y(t) denote the position of the spaceship at time t. Find y(t) if y(0) = 1/10 .


(c) What is the average height of the spaceship over the interval between t = 1 and t = 3 hours?

Expert Solution
Step 1

Given,

Velocity of the spaceship = v(t)

vt =3t2 +2t 

 

Step 2

(a)

To find how far  the spaceship progressed over time  interval [0,3] 

In the time interval [0,3] spaceship progressed = 03v(t)dt 

=03v(t)dt

=033t2 +2tdt 

Doing the integration

=3t33 +2t2203                                        because xndx = xn+1n+1

=t3 +t203 

Substituting the limits

=33 +32 - 03 -02

= 27+9 = 36                                       Answer   

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