A spaceship approaches Earth with a velocity v=0.65 c. A spaceship- based scientist determines that the area of a rectangle and of an equilateral triangle are equal. Consider that the two shapes are coplanar with v; their orientation relative to v is shown in the figure. Then, an Earth-based observer determines that two areas are smaller than the areas determined by the scientist, with the rectangular area larger than the triangle.
A spaceship approaches Earth with a velocity v=0.65 c. A spaceship- based scientist determines that the area of a rectangle and of an equilateral triangle are equal. Consider that the two shapes are coplanar with v; their orientation relative to v is shown in the figure. Then, an Earth-based observer determines that two areas are smaller than the areas determined by the scientist, with the rectangular area larger than the triangle.
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Transcribed Image Text:A spaceship approaches Earth with a velocity v=0.65 c. A spaceship-
based scientist determines that the area of a rectangle and of an
equilateral triangle are equal. Consider that the two shapes are
coplanar with v; their orientation relative to v is shown in the figure.
Then, an Earth-based observer determines that two areas are
smaller than the areas determined by the scientist, with the
rectangular area larger than the triangle.
Reference frane of
A spaceship-based
Reference
observer
frame of Earth-
based observer
15
is asking if its true or false?
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