A solvent passes through a chromatography column in 3.09 min, but the solute requires 9.80 min. The volume of the stationary phase is 0.165 times the volume of the mobile phase in the column (Vs = 0.165VM). %3D What is the distribution constant, Kp, for this system? Kp = 12.12 Incorrect An open tubular chromatography column is 30.2 m long with an inner diameter of 0.513 mm. The inside wall is coated with a layer of 3.00 µm thick stationary phase. Unretained solute passes through the column in 3.59 min (tm), and a certain solute has a retention time of 16.92 min (tr). What is the volume flow rate? mL volume flow rate: 3.689 x10° min Incorrect Calculate the distribution constant, Kp. Kp = 6.96 x10¬4 Incorrect
A solvent passes through a chromatography column in 3.09 min, but the solute requires 9.80 min. The volume of the stationary phase is 0.165 times the volume of the mobile phase in the column (Vs = 0.165VM). %3D What is the distribution constant, Kp, for this system? Kp = 12.12 Incorrect An open tubular chromatography column is 30.2 m long with an inner diameter of 0.513 mm. The inside wall is coated with a layer of 3.00 µm thick stationary phase. Unretained solute passes through the column in 3.59 min (tm), and a certain solute has a retention time of 16.92 min (tr). What is the volume flow rate? mL volume flow rate: 3.689 x10° min Incorrect Calculate the distribution constant, Kp. Kp = 6.96 x10¬4 Incorrect
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
![A solvent passes through a chromatography column in 3.09 min, but the solute requires 9.80 min.
The volume of the stationary phase is 0.165 times the volume of the mobile phase in the column (Vs = 0.165VM).
%3D
What is the distribution constant, Kp, for this system?
Kp = 12.12
Incorrect
An open tubular chromatography column is 30.2 m long with an inner diameter of 0.513 mm. The inside wall is coated
with a layer of 3.00 µm thick stationary phase. Unretained solute passes through the column in 3.59 min (tm), and a certain
solute has a retention time of 16.92 min (tr).
What is the volume flow rate?
mL
volume flow rate: 3.689 x10°
min
Incorrect
Calculate the distribution constant, Kp.
Kp =
6.96 x10¬4
Incorrect](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F008fa3ca-ae4e-445e-a120-b7054bcb4952%2F77ea92df-7ce3-40ad-9f5b-ead0fc344da9%2Fxqro33j.png&w=3840&q=75)
Transcribed Image Text:A solvent passes through a chromatography column in 3.09 min, but the solute requires 9.80 min.
The volume of the stationary phase is 0.165 times the volume of the mobile phase in the column (Vs = 0.165VM).
%3D
What is the distribution constant, Kp, for this system?
Kp = 12.12
Incorrect
An open tubular chromatography column is 30.2 m long with an inner diameter of 0.513 mm. The inside wall is coated
with a layer of 3.00 µm thick stationary phase. Unretained solute passes through the column in 3.59 min (tm), and a certain
solute has a retention time of 16.92 min (tr).
What is the volume flow rate?
mL
volume flow rate: 3.689 x10°
min
Incorrect
Calculate the distribution constant, Kp.
Kp =
6.96 x10¬4
Incorrect
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