A solution was prepared by dissolving 1210 mg of K3Fe(CN)6 (329.2 g/mol) in sufficient water to give 785 mL. Calculate b) the weight/volume percentage of K3Fe(CN)6, the number of millimoles of K+ in 35.0 mL of this solution, and the ppm of Fe(CN)63- IReferences)on stoic Aa the molar analytical concentration of K3 Fe (CN),Molar analytical concentration4.68x10^-3 Mthe molar concentration of K*.Molar concentration = 1.40x10^-2 M-3.the molar concentration of Fe (CN),Molar concentration = 4.68x10^-3 MCorrectCorrectb the weight/volume percentage of K3 Fe (CN)(1/M)% (w/v)the number of millimoles of K in 35.0 mL of this solution.Weight/volume percentage =mmol3-ppm Fe (CN),ppmSubmit

Given, Mass of K3Fe(CN)6 = 1210 mg Volume of K3Fe(CN)6 solution = 785 mL Molar analytical…

Answered: A solution was prepared by dissolving…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A solution was prepared by dissolving 1210 mg of K₃Fe(CN)₆(329.2 g/mol) in sufficient water to give 785 mL. Calculate b) the weight/volume percentage of K₃Fe(CN)_6,the number of millimoles of K⁺in 35.0 mL of this solution, and the ppm of Fe(CN)₆^3-

IReferences)
on stoic A
a the molar analytical concentration of K3 Fe (CN),
Molar analytical concentration
4.68x10^-3 M
the molar concentration of K*.
Molar concentration = 1.40x10^-2 M
-
3.
the molar concentration of Fe (CN),
Molar concentration = 4.68x10^-3 M
Correct
Correct
b the weight/volume percentage of K3 Fe (CN)
(1/M)
% (w/v)
the number of millimoles of K in 35.0 mL of this solution.
Weight/volume percentage =
mmol
3-
ppm Fe (CN),
ppm
Submit

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