A solution of tyrosine is made by dissolving 0.005 mole of tyrosine in 1.0 L of 0. M NAOH solution. Draw the structure of the principal chemical form of tyrosine found in this solution at equilibrium given the data below. NH2 pKa (CO2H) = 2.41 pka (NH2) = 8.67 pKa (OH) = 11.01 CHCH2 HO- CO2H

A solution of tyrosine is made by dissolving 0.005 mole of tyrosine in 1.0 L of 0. M NAOH solution. Draw the structure of the principal chemical form of tyrosine found in this solution at equilibrium given the data below. NH2 pKa (CO2H) = 2.41 pka (NH2) = 8.67 pKa (OH) = 11.01 CHCH2 HO- CO2H

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter16: Reactions Between Acids And Bases

Section: Chapter Questions

Problem 16.66QE: Write the chemical equilibrium and expression for the equilibrium constants for the ionization of...

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Applications of Molecular Spectroscopy

When light sources pass through the diffraction grating then light splits into different wavelengths. The light source produces two types of patterns that are shown as destructive and non-destructive. The light source is in the form of quanta that is quantitation.

Question

A solution of tyrosine is made by dissolving 0.005 mole of tyrosine in 1.0 L of 0.1
M NaOH solution. Draw the structure of the principal chemical form of tyrosine found in
this solution at equilibrium given the data below.
NH2
pKa (CO2H) = 2.41
pKa (NH2) = 8.67
pka (OH) = 11.01
CHCH2
OH
CO2H

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