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A solution of the weak acid HA is prepared by dissolving 2.20 g of HA in 100.0 mL water. The solution is titrated, and the equivalence point is reached after 31.1 mL of 0.500 M NaOH is dispensed. Calculate the molar mass of HA. molar mass: g/mol At the equivalence point in this titration, how can the solution pH be described? acidic basic neutral

A solution of the weak acid HA is prepared by dissolving 2.20 g of HA in 100.0 mL water. The solution is titrated, and the equivalence point is reached after 31.1 mL of 0.500 M NaOH is dispensed. Calculate the molar mass of HA. molar mass: g/mol At the equivalence point in this titration, how can the solution pH be described? acidic basic neutral

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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A solution of the weak acid HA is prepared by dissolving 2.20 g of HA in 100.0 mL water. The solution is titrated, and the equivalence point is reached after 31.1 mL of 0.500 M NaOH is dispensed. Calculate the molar mass of HA. molar mass: g/mol At the equivalence point in this titration, how can the solution pH be described? acidic basic O neutral
Transcribed Image Text:A solution of the weak acid HA is prepared by dissolving 2.20 g of HA in 100.0 mL water. The solution is titrated, and the equivalence point is reached after 31.1 mL of 0.500 M NaOH is dispensed. Calculate the molar mass of HA. molar mass: g/mol At the equivalence point in this titration, how can the solution pH be described? acidic basic O neutral
Expert Solution
Step 1

Given: Mass of HA = 2.20 g.

Concentration of NaOH = 0.500 M

Volume of NaOH solution required = 31.1 mL = 0.0311 L                                 (Since 1 L = 1000 mL)

The moles of NaOH required = concentration × volume in L = 0.500 × 0.0311 = 0.01555 mol.

 

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