A solution of pH 3.88 is prepared by dissolving sufficient sodium formate, NaHCOO(s), in 1.50 L of 0.100 M formic acid (HCOOH). How many mol of NaOH(s) must be added to change the pH by 0.65 units? Assume no volume changes on addition of solids. Data: K₂(HCOOH) = 1.8 × 10-4 0.025 0.070 0.10 0.055
A solution of pH 3.88 is prepared by dissolving sufficient sodium formate, NaHCOO(s), in 1.50 L of 0.100 M formic acid (HCOOH). How many mol of NaOH(s) must be added to change the pH by 0.65 units? Assume no volume changes on addition of solids. Data: K₂(HCOOH) = 1.8 × 10-4 0.025 0.070 0.10 0.055
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.30QE
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![A solution of pH 3.88 is prepared by dissolving sufficient sodium formate, NaHCOO(s), in 1.50 L of 0.100 M formic acid (HCOOH).
How many mol of NaOH(s) must be added to change the pH by 0.65 units? Assume no volume changes on addition of solids.
Data:
K,(HCOOH) = 1.8 × 10-4
0.025
0.070
0.10
0.055](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fca6b5de9-d666-4be4-bec5-372f49facd74%2Fd471de26-7508-45c4-ba06-90755cb21617%2Fjg1x1bo_processed.png&w=3840&q=75)
Transcribed Image Text:A solution of pH 3.88 is prepared by dissolving sufficient sodium formate, NaHCOO(s), in 1.50 L of 0.100 M formic acid (HCOOH).
How many mol of NaOH(s) must be added to change the pH by 0.65 units? Assume no volume changes on addition of solids.
Data:
K,(HCOOH) = 1.8 × 10-4
0.025
0.070
0.10
0.055
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