QUESTION 9A solution of hydrogen peroxide was titrated with a solution of potassium permanganate (see reaction). 5 H 2O 2(aq) + 2 KMnO 4(aq) + 3 H 2SO 4 -> 5 O 2(g) + 2 MnSO 4(aq) + K 2SO 4(aq) + 8 H 2O(l)It required 75.00 mL of 0.1626 M KMnO 4 to titrate 3.564 g of the solution containing hydrogen peroxide. What was the mass percentage of H 2O 2 in the solution? Key Concept:Reactions in solution. The proportional way that compounds react, e.g. aA + bB →cC + dD. This tells us that we can find the mol of one if we know the mol of another in the reaction. Using the proportional behavior described by the balanced reaction. If there are 5 mol of B. We would say the mol of A must be 5 mol B* (A mol A/b mol B). In solutions we can determine moles of each using n = M*V, where n = mol, M = molarity and V = volume. Strategy: molarity of permanganate and volume of permanaganate solution → mole of permanganate → mol hydrogen peroxide → mass of peroxide in solution; this + mass of solution→mass %

The number of moles is a ratio of the mass of a substance to the molar mass of the substance.…

Answered: A solution of hydrogen peroxide was…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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QUESTION 9

A solution of hydrogen peroxide was titrated with a solution of potassium permanganate (see reaction).
5 H ₂O ₂(aq) + 2 KMnO ₄(aq) + 3 H ₂SO ₄ -> 5 O ₂(g) + 2 MnSO ₄(aq) + K ₂SO ₄(aq) + 8 H ₂O(l)It required 75.00 mL of 0.1626 M KMnO ₄ to titrate 3.564 g of the solution containing hydrogen peroxide. What was the mass percentage of H ₂O ₂ in the solution?

Key Concept:Reactions in solution. The proportional way that compounds react, e.g. aA + bB →cC + dD. This tells us that we can find the mol of one if we know the mol of another in the reaction. Using the proportional behavior described by the balanced reaction. If there are 5 mol of B. We would say the mol of A must be 5 mol B* (A mol A/b mol B). In solutions we can determine moles of each using n = M*V, where n = mol, M = molarity and V = volume.
Strategy: molarity of permanganate and volume of permanaganate solution → mole of permanganate → mol hydrogen peroxide → mass of peroxide in solution; this + mass of solution→mass %

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