A solution of HNO3 is standardized by reaction with pure sodium carbonate. 2H+ Na₂CO3 →→ 2Na+H₂O + CO₂ A volume of 24.14 ± 0.06 mL of HNO3 solution was required for complete reaction with 0.9021 ± 0.0009 g of Na2CO3, (FM 105.988 ± 0.001). Find the molarity of the HNO3 and its absolute uncertainty.
A solution of HNO3 is standardized by reaction with pure sodium carbonate. 2H+ Na₂CO3 →→ 2Na+H₂O + CO₂ A volume of 24.14 ± 0.06 mL of HNO3 solution was required for complete reaction with 0.9021 ± 0.0009 g of Na2CO3, (FM 105.988 ± 0.001). Find the molarity of the HNO3 and its absolute uncertainty.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A solution of HNO3 is standardized by reaction with pure sodium carbonate.
2H+ Na₂CO, →→ 2Na+H₂O + CO₂
A volume of 24.14 ± 0.06 mL of HNO3 solution was required for complete reaction with 0.9021 ± 0.0009 g of
Na2CO3, (FM 105.988 ± 0.001). Find the molarity of the HNO3 and its absolute uncertainty.
Number
[HNO,]= 0.7042
M
±
Number
0.002
M
Note: Significant figures are graded for this
problem. To avoid rounding errors, do not
round your answers until the very end of
your calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1e4e9d3f-c264-417d-81c5-7b32f78013b4%2F044da6da-9e88-47ed-b298-fc3168342047%2Fvambhi_processed.png&w=3840&q=75)
Transcribed Image Text:A solution of HNO3 is standardized by reaction with pure sodium carbonate.
2H+ Na₂CO, →→ 2Na+H₂O + CO₂
A volume of 24.14 ± 0.06 mL of HNO3 solution was required for complete reaction with 0.9021 ± 0.0009 g of
Na2CO3, (FM 105.988 ± 0.001). Find the molarity of the HNO3 and its absolute uncertainty.
Number
[HNO,]= 0.7042
M
±
Number
0.002
M
Note: Significant figures are graded for this
problem. To avoid rounding errors, do not
round your answers until the very end of
your calculations.
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