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A solution of citric acid (F3C6H507) with a known concentration of 0.200 M H3C6H507 is titrated with a 0.750 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 25.0 mL H3CH₂O7 according to the following balanced chemical equation: H3C6H₂O₂ + 3 NaOH - Na C6H5O7+ 3 H₂O

A solution of citric acid (F3C6H507) with a known concentration of 0.200 M H3C6H507 is titrated with a 0.750 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 25.0 mL H3CH₂O7 according to the following balanced chemical equation: H3C6H₂O₂ + 3 NaOH - Na C6H5O7+ 3 H₂O

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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what is the correct unit next to the number 1000? Use dimensional analysis for the answer
0.200 malHest507 LHEMS07 0.200 mol H₂CH₂O7 LH₂C₂H₂O7 X 25.0 L H₂C,H,O, 1000 ↑ 25.0 1000 A solution of citric acid (F3C6H507) with a known concentration of 0.200 M H3C6H5O7| is titrated with a 0.750 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 25.0 mL H3CH₂O7 according to the following balanced chemical equation: H3C6H₂O₂ + 3 NaOH Na-C6H5O7+ 3 H₂O LHC6H5O7 3 mol NaOH 1 mol H₂C,H,O, 1000 1 1 L NaOH 0.750 mol NaOH 0.020 X mol H₂C6H5O7 6.67 1 2.00 x 104 20.0 3 1000 mL NaOH 1 L NaOH 0.200 mol NaOH mol NaOH malH3C6H5O7 = 20.0 mL NaOH 2 0.001 mL H3C6H5O7 MH3C6H5O7 3 M NaOH g H3C6H₂O7 g NaOH X 2.22 0.750 LNaOH mL NaOH 1 0.750 25.0 LNaOH mol NaOH 11.25 LH3C6H₂O7 15.0 X
Transcribed Image Text:0.200 malHest507 LHEMS07 0.200 mol H₂CH₂O7 LH₂C₂H₂O7 X 25.0 L H₂C,H,O, 1000 ↑ 25.0 1000 A solution of citric acid (F3C6H507) with a known concentration of 0.200 M H3C6H5O7| is titrated with a 0.750 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 25.0 mL H3CH₂O7 according to the following balanced chemical equation: H3C6H₂O₂ + 3 NaOH Na-C6H5O7+ 3 H₂O LHC6H5O7 3 mol NaOH 1 mol H₂C,H,O, 1000 1 1 L NaOH 0.750 mol NaOH 0.020 X mol H₂C6H5O7 6.67 1 2.00 x 104 20.0 3 1000 mL NaOH 1 L NaOH 0.200 mol NaOH mol NaOH malH3C6H5O7 = 20.0 mL NaOH 2 0.001 mL H3C6H5O7 MH3C6H5O7 3 M NaOH g H3C6H₂O7 g NaOH X 2.22 0.750 LNaOH mL NaOH 1 0.750 25.0 LNaOH mol NaOH 11.25 LH3C6H₂O7 15.0 X
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