A solution is prepared by mixing 45.68 g of carbon disulfide (CS2, 76.13 g/mol) with 16.42 g of acetonitrile (CH3CN, 41.06 g/mol). What is the mole fraction of CS2 in the vapor phase at 20 °C? Substance Vapor Pressure @ 20 °C (torr) Carbon disulfide 357 Acetonitrile 89.5
A solution is prepared by mixing 45.68 g of carbon disulfide (CS2, 76.13 g/mol) with 16.42 g of acetonitrile (CH3CN, 41.06 g/mol). What is the mole fraction of CS2 in the vapor phase at 20 °C?
|
Substance |
Vapor Pressure @ 20 °C (torr) |
|
Carbon disulfide |
357 |
|
Acetonitrile |
89.5 |
We know that, the partial pressure of solute in vapor phase is equal to the mole fraction of solute above the solution multiplied by the total pressure above the solution. We can use this relation to determine the mole fraction of solute in the vapor phase.
Psolute = Xsolute x PT
Where, Psolute is the vapor pressure of the solute
Xsolute is the mole fraction of the solute
PT is the total pressure.
Given, vapor pressure of carbon disulfide, Psolute = 357 Torr
vapor pressure of acetonitrile = 89.5 Torr
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