A solution is made by mixing 48. g of heptane (C₂H₁6) and 39. g of chloroform (CHC13). 16 Calculate the mole fraction of heptane in this solution. Round your answer to 2 significant digits. X

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Chapter1: Chemical Foundations
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**Problem Statement:**

A solution is made by mixing 48. g of heptane (\( \text{C}_7\text{H}_{16} \)) and 39. g of chloroform (\( \text{CHCl}_3 \)).

Calculate the mole fraction of heptane in this solution. Round your answer to 2 significant digits.

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**Note:** In this problem, you need to determine the mole fraction of heptane in a binary solution composed of heptane and chloroform. To solve, first calculate the number of moles of each compound, then use the mole fraction formula.
Transcribed Image Text:**Problem Statement:** A solution is made by mixing 48. g of heptane (\( \text{C}_7\text{H}_{16} \)) and 39. g of chloroform (\( \text{CHCl}_3 \)). Calculate the mole fraction of heptane in this solution. Round your answer to 2 significant digits. [Input Box] --- **Note:** In this problem, you need to determine the mole fraction of heptane in a binary solution composed of heptane and chloroform. To solve, first calculate the number of moles of each compound, then use the mole fraction formula.
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