**Problem Statement:**A solution is made by mixing 48. g of heptane (\( \text{C}_7\text{H}_{16} \)) and 39. g of chloroform (\( \text{CHCl}_3 \)).Calculate the mole fraction of heptane in this solution. Round your answer to 2 significant digits.[Input Box]---**Note:** In this problem, you need to determine the mole fraction of heptane in a binary solution composed of heptane and chloroform. To solve, first calculate the number of moles of each compound, then use the mole fraction formula.

The mass of heptane is = 48. gThe mass of chloroform is = 39 gThe mole fraction of heptane in this solution is =?We know that the molar mass of heptane = 100.21 g/molThe molar mass of chloroform is = 119.38 g/molWe know that the number of moles of a substance is calculated by the ratio of mass in gram to the molar mass of that substance.

Answered: A solution is made by mixing 48. g of…

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A solution is made by mixing 48. g of heptane (C₂H₁6) and 39. g of chloroform (CHC13). 16 Calculate the mole fraction of heptane in this solution. Round your answer to 2 significant digits. X

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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