### Colligative Properties Calculation#### Problem StatementA solution is made by dissolving 0.626 mol of nonelectrolyte solute in 849 g of benzene. Calculate the freezing point, \( T_f \), and boiling point, \( T_b \), of the solution. Constants can be found in the table of colligative constants.#### Calculation Fields**Freezing Point, \( T_f \):**\[ T_f = \_\_\_\_ \degree C \]**Boiling Point, \( T_b \):**\[ T_b = \_\_\_\_ \degree C \]

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A solution is made by dissolving 0.626 mol of nonclectrolyte solute in 849 g of benzene. Calculate the frcezing point, T, and boiling point, T, of the solution. Constants can be found in the table of colligative constants. T, =

A solution is made by dissolving 0.626 mol of nonclectrolyte solute in 849 g of benzene. Calculate the frcezing point, T, and boiling point, T, of the solution. Constants can be found in the table of colligative constants. T, =

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

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### Colligative Properties Calculation

#### Problem Statement
A solution is made by dissolving 0.626 mol of nonelectrolyte solute in 849 g of benzene. Calculate the freezing point, \( T_f \), and boiling point, \( T_b \), of the solution. Constants can be found in the table of colligative constants.

#### Calculation Fields
**Freezing Point, \( T_f \):**

\[ T_f = \_\_\_\_ \degree C \]

**Boiling Point, \( T_b \):**

\[ T_b = \_\_\_\_ \degree C \]

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