A solution is 0.015M in Pb2+ and 0.015M in Ag+. As Cl- is introduced to the solution, the solids AgCl and PbCl2 are formed. Identify the order of precipitation of the two solids. (Ksp AgCl = 1.8x10-10; Ksp PbCl2 = 1.7x10-5) PbCl2 precipitates first followed by AgCl AgCl precipitates first followed by PbCl2 AgCl and PbCl2 precipitates at the same time

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A solution is 0.015M in Pb2+ and 0.015M in Ag+.
As Cl- is introduced to the solution, the solids AgCl
and PbCl2 are formed.
Identify the order of precipitation of the two solids.
(Ksp AgCl = 1.8x10-10 ; Ksp PbCl2 = 1.7x10-5)
PbCl2 precipitates first followed by AgCl
AgCl precipitates first followed by PbCl2
AgCl and PbCl2 precipitates at the same time
Transcribed Image Text:A solution is 0.015M in Pb2+ and 0.015M in Ag+. As Cl- is introduced to the solution, the solids AgCl and PbCl2 are formed. Identify the order of precipitation of the two solids. (Ksp AgCl = 1.8x10-10 ; Ksp PbCl2 = 1.7x10-5) PbCl2 precipitates first followed by AgCl AgCl precipitates first followed by PbCl2 AgCl and PbCl2 precipitates at the same time
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