A solution contains 0.302 M ammonium bromide and 0.201 M ammonia. The pH of this solution is

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Chapter1: Chemical Foundations
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**Solution Details:**

A solution contains **0.302 M ammonium bromide** and **0.201 M ammonia**.

**Objective:**

Determine the pH of this solution.

---

To calculate the pH of a solution containing both ammonium bromide and ammonia, apply the Henderson-Hasselbalch equation, which is used for buffer solutions containing a weak base and its conjugate acid. Ammonia (NH₃) is the weak base, and ammonium bromide (NH₄Br) provides the conjugate acid (NH₄⁺). 

The equation is:
\[ \text{pH} = \text{pK}_a + \log \left(\frac{[\text{base}]}{[\text{acid}]}\right) \]

Where:
- \([\text{base}]\) is the concentration of ammonia (0.201 M).
- \([\text{acid}]\) is the concentration of ammonium bromide (0.302 M).
- \(\text{pK}_a\) is the negative logarithm of the acid dissociation constant of the ammonium ion. 

This setup allows for the calculation of the pH to understand the acidity/basicity of the solution.
Transcribed Image Text:**Solution Details:** A solution contains **0.302 M ammonium bromide** and **0.201 M ammonia**. **Objective:** Determine the pH of this solution. --- To calculate the pH of a solution containing both ammonium bromide and ammonia, apply the Henderson-Hasselbalch equation, which is used for buffer solutions containing a weak base and its conjugate acid. Ammonia (NH₃) is the weak base, and ammonium bromide (NH₄Br) provides the conjugate acid (NH₄⁺). The equation is: \[ \text{pH} = \text{pK}_a + \log \left(\frac{[\text{base}]}{[\text{acid}]}\right) \] Where: - \([\text{base}]\) is the concentration of ammonia (0.201 M). - \([\text{acid}]\) is the concentration of ammonium bromide (0.302 M). - \(\text{pK}_a\) is the negative logarithm of the acid dissociation constant of the ammonium ion. This setup allows for the calculation of the pH to understand the acidity/basicity of the solution.
The compound **ethylamine** is a weak base like ammonia. A solution contains **0.270 M C₂H₅NH₃⁺** and **0.184 M ethylamine, C₂H₅NH₂**. 

The pH of this solution is [blank].
Transcribed Image Text:The compound **ethylamine** is a weak base like ammonia. A solution contains **0.270 M C₂H₅NH₃⁺** and **0.184 M ethylamine, C₂H₅NH₂**. The pH of this solution is [blank].
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