A solid substance has a density Ppå at a temperature Tō. If its temperature is increased by an amount AT, show that its density at the higher temperature is given by the following equation. (Submit a file with a maximum size of 1 MB.) P = P0/(1+BAT)
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- The volume of an automobile tire is 2.5x10^-2m^3. The pressure of the air in the tire is 3.3 atm and the temperature is 25C°. What is the mass of air in grams? The mean molecular mass of air is 29g. Calculate to 2 decimals.The reservoir in Figure contains water and immiscible oil at a temperature of 20 ° C. What is the height h in centimeters if the density of the oil is 898 kg / m3?Air flows at 210 m/s through the pipe. The temperature is 400 K and the absolute stagnation pressure is 280 kPa. Assume isentropic flow. For air R = 286.9 J/[kg - K] and k=1.40. (Figure 1) Figure 0.3 m
- The tidal lung volume of human breathing, representing the amount of air inhaled and exhaled in a normal breath, is 500 cm³. (Assume atmospheric pressure.) (a) What is the number of molecules of air inhaled with each human breath when the air temperature is 25.0°C? molecules (b) If the molar mass of air is 28.96 g/mol, what is the mass (in g) of air molecules inhaled with each breath? (Assume the air temperature is 25.0°C.) g (c) It has been calculated that all of the air in Earth's atmosphere could be collected into a sphere of diameter 1,999 km at a pressure of 1.00 atm. What is the mass (in kg) of the air in Earth's atmosphere? (Assume the density of air used in this calculation was 1.225 kg/m³.) kg (d) If all 7 billion humans on Earth inhaled simultaneously, what percentage of the atmosphere would be inhaled during this process? (Assume the air temperature is 25.0°C everywhere on Earth.) %Gauge pressure is the pressure read by a pressure gauge. The gauge pressure will be zero if the pressure is the same as the general atmospheric pressure, because the gauge measures only the excess above atmospheric pressure. The actual pressure will thus be atmospheric pressure plus gauge pressure. Atmospheric pressure is about 14 pounds per square inch. The Rankine temperature scale is the Fahrenheit verson of the absolute temperature, and absolute zero in Rankine is about -460 F. Now, imagine a football has been stored in a warm locker room at a temperature of 71 F, and has a gauge pressure of 12.5 pounds per square inch. Next, it is taken outside and cooled to 40 F. What will the gauge pressure be after this is done?(1) The specific gravity of a urine sample is found to be 1.110 at a temperature of 24C. The specific gravity of this urine was determined with a urinometer. What is the corrected specific gravity value of this sample? (2) We've learned that urinometers are usually calibrated at 15 C and that we have to correct for samples that are above or below this temperature. This is because the density of a liquid changes with temperature. Using the density formula, explain why temperature affects the density of a liquid. Explain what happens to the density of a liquid as the temperature is raised and lowered.
- Platinum 21.4 x 10 Uranium 18.7x 10 O Description 5 DETAILS SERCP11 7.5.P.044. A 737-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. m/s (b) Find the period of its revolution. (c) Find the gravitational force acting on it. Submit AnswerIn a hypothetical diesel engine the fuel is compressed from 528mL to 39.7 mL. This rasies the temperature of the fuel form 25°C to its ignition temperature of 210°C. If the fuel begins at 1.00atm, what is the pressure of the fuel at its ignition temperature.? Express your answer to 1 decimal place. Be sure to use the proper abbreviation of the UNITSJanice is grilling a steak for her July 4th barbecue dinner. The steak initially weighs 300 grams and is 25 mm thick. After grilling it for a while, she considers the steak done, and measures it again: it now weighs 215 grams, and is 15 mm thick. For both the cooked and uncooked steak, she uses the thumb-test to determine the done-ness, i.e. she uses her thumb (area ~5cm2) to push down with a force of 5 N. The uncooked steak compresses by 7 mm, and the cooked steak by 2 mm. The change in elasticity of the steak on cooking is due partly to the loss of water volume (so that existing bonds get closer together) and partly to the creation of new bonds. Assume all of the difference in raw vs. cooked steak thickness is due to water loss that makes it thinner (25 mm thick in the uncooked steak, versus 15 mm thick in the cooked steak), and that the other dimensions of the steak (length and width) have not changed. By what percentage has the steak's volume decreased from the original value?…
- Janice is grilling a steak for her July 4th barbecue dinner. The steak initially weighs 300 grams and is 25 mm thick. After grilling it for a while, she considers the steak done, and measures it again: it now weighs 215 grams, and is 15 mm thick. For both the cooked and uncooked steak, she uses the thumb-test to determine the done-ness, i.e. she uses her thumb (area ~5cm2) to push down with a force of 5 N. The uncooked steak compresses by 7 mm, and the cooked steak by 2 mm. Calculating elasticity What is the elasticity of the raw steak? Express your answer in Pascals but without including the units in your answer. What is the elasticity of the cooked steak? Express your answer in Pascals, but without including the units.When the coefficient of linear expansion, a, and the temperature change, T-T, are large, a length L, of a solid substance expands in length to a(T, -T₂) L₁ = L₁e O L=L[1 + a(Tƒ– T;)]. ○ Ly=al (Ty-T). O L=L[1 + In(a(T₁-T))]. a(T, I₂ = ₁₂₁[ 1 + ª²(²₁-7)].