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A solid sphere of iron has a radius of 23.2 cm at a temperature of 22.0°C. Calculate the change in surface area of the sphere at a temperature of 53.0°C Coefficient of linear expansion of iron: a = 11x10-6/C° Coefficient of area expansion of iron: g = 22 x10-6/C° Surface area of a sphere: A = 4(pi)r2

A solid sphere of iron has a radius of 23.2 cm at a temperature of 22.0°C. Calculate the change in surface area of the sphere at a temperature of 53.0°C Coefficient of linear expansion of iron: a = 11x10-6/C° Coefficient of area expansion of iron: g = 22 x10-6/C° Surface area of a sphere: A = 4(pi)r2

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A solid sphere of iron has a radius of 23.2 cm at a temperature of 22.0°C. Calculate the change in surface area of the sphere at a temperature of 53.0°C               

 Coefficient of linear expansion of iron: a = 11x10-6/C°

Coefficient of area expansion of iron: g = 22 x10-6/C°

Surface area of a sphere: A = 4(pi)r2

Intensity level: m T = 2n, k B=10log I. Frequency: f = T Intensity level difference: Angular frequency: k w = 2n f AB =10log I, m PV = nRT, where R = 8.31 J/mole-K Maximum Velocity, Acceleration: A2n f Ao = A(2nf} Umax = A@ = a max = PV = constant, PIV1 = P2V2 A = (27 f) а max Intensity: Simple pendulum: I= Pav 4ar? T= 2n= Doppler Shift: Moving observer: f' = f(v+vo)/v Speed sound temperature: Moving source: f' = f(v)/ ( v-vs) v= f2 Where vo = velocity of observer, vs is the speed of the source, and v is the speed of sound T U = (331m/s), 273K Intensity of a wave: power Beat frequency fB \f2- fil I= %3D area A bol
Transcribed Image Text:Intensity level: m T = 2n, k B=10log I. Frequency: f = T Intensity level difference: Angular frequency: k w = 2n f AB =10log I, m PV = nRT, where R = 8.31 J/mole-K Maximum Velocity, Acceleration: A2n f Ao = A(2nf} Umax = A@ = a max = PV = constant, PIV1 = P2V2 A = (27 f) а max Intensity: Simple pendulum: I= Pav 4ar? T= 2n= Doppler Shift: Moving observer: f' = f(v+vo)/v Speed sound temperature: Moving source: f' = f(v)/ ( v-vs) v= f2 Where vo = velocity of observer, vs is the speed of the source, and v is the speed of sound T U = (331m/s), 273K Intensity of a wave: power Beat frequency fB \f2- fil I= %3D area A bol
Area of circle: A = Tr? Rate of flow Q = Av t = F(sin0)r T = Fl, wherel= lever arm Bernoulli's equation: 1 P+ + pgy, = P, + 1 pv,´ + pgy, Equilibrium: Te = T - 273.15°C Στ=0 9 T = -T. +32 5 Non-equilibrium: 5 Tc =-(T, - 32) Στ= Ια Тетреrature: Moment of inertial for a point mass revolving about a center at a distance r: ΔL L,ΔΤ AA = y A,AT Y = 2a AV = BVAT B = 3a I= Mr? Kinetic Energy: Specific Heat: Translational: ½ mv² Rotational: ½ Im? (J/kg. 'C) mAT Q = mc(T, –T,) Angular speed o =v/r Qcold =-Qhot Tensile strain: EQ = 0 Latent Heat: F AL L. Y -Young's modulus phase change: Q=±mL Energy Transfer: ΔΤ P = At Density: Ar M p = V (kg/m²) Thermal conductivity: Pressure: (T, – T.) P = kA L. F P= A (Ра) Hooke's Law: F =-kx P = P, + pgh Acceleration in simple harmonic motion: Archimedes' principle: k a = B = P fuidV fa m fluid8 Elastic potential energy: РЕ, %3D -kx² 2 Equation of flow continuity: Av, = A,v, Period:
Transcribed Image Text:Area of circle: A = Tr? Rate of flow Q = Av t = F(sin0)r T = Fl, wherel= lever arm Bernoulli's equation: 1 P+ + pgy, = P, + 1 pv,´ + pgy, Equilibrium: Te = T - 273.15°C Στ=0 9 T = -T. +32 5 Non-equilibrium: 5 Tc =-(T, - 32) Στ= Ια Тетреrature: Moment of inertial for a point mass revolving about a center at a distance r: ΔL L,ΔΤ AA = y A,AT Y = 2a AV = BVAT B = 3a I= Mr? Kinetic Energy: Specific Heat: Translational: ½ mv² Rotational: ½ Im? (J/kg. 'C) mAT Q = mc(T, –T,) Angular speed o =v/r Qcold =-Qhot Tensile strain: EQ = 0 Latent Heat: F AL L. Y -Young's modulus phase change: Q=±mL Energy Transfer: ΔΤ P = At Density: Ar M p = V (kg/m²) Thermal conductivity: Pressure: (T, – T.) P = kA L. F P= A (Ра) Hooke's Law: F =-kx P = P, + pgh Acceleration in simple harmonic motion: Archimedes' principle: k a = B = P fuidV fa m fluid8 Elastic potential energy: РЕ, %3D -kx² 2 Equation of flow continuity: Av, = A,v, Period:
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