A solid shaft is to transmit 250 kW at 180 rpm. The torsional shear stress is not to exceed 110 MPa. Without changing the length, material, and allowable stress, it is replaced by a hollowed section whose internal diameter equals 0.6 of the external diameter. Determine the diameter of the solid shaft (in mm).

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A: To determine:The magnitude of maximum shear stress in the shaft()

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Q: The drive shaft of the motor is made of a material having an allowable shear stress of τallow= 72…

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Q: solid shaft is transmitting 9 KW at 550 r.p.m. Determine the diameter of the shaft if the maximum…

A: for solution refer below images.

Q: A solid shaft is transmitting 1 MW at 250 r.p.m. Determine the diameter of the shaft if the maximum…

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Q: A circular solid shaft has a diameter of 60 mm and is subjected to a torque load of 8.7 kN•m.…

A: Given      Diameter, d = 60 mm  Torque load, T = 8.7 kN•m

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Q: (6) A solid shaft is used to transmit 75kW @ 550rpm. If the shaft design stress will not exceed…

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Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.