A solid object weighs 18.58 N in air. When it is suspended from a scale and submerged in water, the scale reads 3.78 N. scale mass water Find the density of the object. (Use 1000.0 kg/m³ for the density of water.) 3
Fluid Pressure
The term fluid pressure is coined as, the measurement of the force per unit area of a given surface of a closed container. It is a branch of physics that helps to study the properties of fluid under various conditions of force.
Gauge Pressure
Pressure is the physical force acting per unit area on a body; the applied force is perpendicular to the surface of the object per unit area. The air around us at sea level exerts a pressure (atmospheric pressure) of about 14.7 psi but this doesn’t seem to bother anyone as the bodily fluids are constantly pushing outwards with the same force but if one swims down into the ocean a few feet below the surface one can notice the difference, there is increased pressure on the eardrum, this is due to an increase in hydrostatic pressure.
![**Title: Calculating the Density of a Submerged Object**
**Problem Statement:**
A solid object weighs 18.58 N in air. When it is suspended from a scale and submerged in water, the scale reads 3.78 N. Calculate the density of the object, using 1000.0 kg/m³ for the density of water.
**Diagrams Explanation:**
The image consists of two diagrams:
1. **Left Diagram:**
- It shows a mass hanging from a scale in the air.
- The scale reads the weight of the mass as 18.58 N.
2. **Right Diagram:**
- It depicts the same mass submerged in a container of water.
- The scale now reads 3.78 N, indicating the apparent weight of the object in water.
**Procedure:**
The object's density can be calculated using the principle of buoyancy. The difference in the object's weight in air and its apparent weight in water is due to the buoyant force, which equals the weight of the water displaced by the object.
**Formulas:**
1. Weight of object in air = \( W_a = 18.58 \, \text{N} \)
2. Apparent weight of object in water = \( W_w = 3.78 \, \text{N} \)
3. Buoyant force = \( W_a - W_w \)
4. Volume of displaced water = Buoyant force / (density of water * gravity)
5. Density of object \( (\rho) = \text{mass} / \text{volume} \)
**Steps to Calculate:**
1. Calculate the buoyant force:
\[ \text{Buoyant force} = 18.58 \, \text{N} - 3.78 \, \text{N} \]
2. Find the volume of the object using the buoyant force:
\[
\text{Volume} = \frac{\text{Buoyant force}}{1000 \, \text{kg/m}^3 \times 9.8 \, \text{m/s}^2}
\]
3. Compute the density of the object:
\[
\rho = \frac{18.58 \, \text{N} / 9.8 \, \text{m/s}^2}{\text{Volume}}
\]
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