6.6AO2.64Ⓒ4,2cm 2.64ст17cmA solid cylindrical conducting shell carries a uniformly distributed current out of the page as shown.An infinite conducting wire carrying a current into the page is located at the center as shown. Whichis a correct application of Ampere's law to solve for the magnetic field B around an Amperian loop ofradius 8.0 cm centered on the center wire? Use the convention that current out of the screen ispositive and current into the screen is negative, so that positive B is counterclockwise and negativeB is clockwise. Take the units of B to be Tesla and to be in SI units as in the list of constants above.Ο Β 2 π (0.07)= + 4.0 μοΟ Β 2 π (0.07)= -6.6 μοΟ Β 2 π (0.08)= + 4.0 μοΟ Β 2 π (0.08)= + 6.6 μοΟ Β 2 π (0.08)= - 4.0 μο

Solution: Use amperes law to solve for the magnetic field. Therefore, draw an ampere loop of radius…

Answered: A solid cylindrical conducting shell…

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