A solid circular rod that is 600 mm long and 20 mm in diameter is subjected to an axial force of P = 50 kN. The elongation of the rod is 8 = 1.40 mm, and its diameter becomes d2 = 19.9837 mm. Assume that the material does not yield. Determine the following: P = 50 kN 600 mm 20 mm P = 50 kN The normal stress is equal to in MPa: The normal Strain is equal to: The modulus of elasticity is equal to in GPa: The changes in diameter (Ad) is equal to in mm: The passion ratio is equal to: The shear modulus is equal to in GPa:

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A solid circular rod that is 600 mm long and 20 mm in diameter is subjected to an axial force of P = 50 kN.
The elongation of the rod is 8 = 1.40 mm, and its diameter becomes d2 = 19.9837 mm. Assume that the
material does not yield. Determine the following:
P = 50 kN
600 mm
20 mm
P = 50 kN
The normal stress is equal to in MPa:
The normal Strain is equal to:
The modulus of elasticity is equal to in GPa:
The changes in diameter (Ad) is equal to in mm:
The passion ratio is equal to:
The shear modulus is equal to in GPa:
Transcribed Image Text:A solid circular rod that is 600 mm long and 20 mm in diameter is subjected to an axial force of P = 50 kN. The elongation of the rod is 8 = 1.40 mm, and its diameter becomes d2 = 19.9837 mm. Assume that the material does not yield. Determine the following: P = 50 kN 600 mm 20 mm P = 50 kN The normal stress is equal to in MPa: The normal Strain is equal to: The modulus of elasticity is equal to in GPa: The changes in diameter (Ad) is equal to in mm: The passion ratio is equal to: The shear modulus is equal to in GPa:
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