A solenoid of diameter 0.2 m has 500 turns per metre. At the centre of this solenoid, a coil of 100 turns is wrapped closely around it. If the current in the so- lenoid changes from zero to 2 A in 1 millisecond, calculate the induced emf developed in the coil.

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A: Number of turns ( N ) = 15 Radius of the coil ( r ) = 10 cm = 0.1 m Current ( I ) = 4.00 sin( 120t )…

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Q: A technician wraps wire around a tube of length 44 cm having a diameter of 7.0 cm. When the windings…

A: dia of tube = 7cm length of wire = 44cm therefore the number of turn N =730 self-inductance of coil…

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Q: A solenoid with 500 turns and a length of 0.2 meters is carrying a current of 2.5 Amperes.…

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Q: Find the current induced in the coil

A: Induced current in the loop is   0.0244  A  Explanation is in steps below :

Q: A small loop of area A = 7.6 mm2 is inside a long solenoid that has n = 927 turns/cm and carries a…

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Q: A coil of 15 turns and radius 10-0cm Surrounds a long solenuvid of radius 2.50cm and 1-00 x 103…

A: The number of turns of the coil, N=15 turns Radius of the coil, rc=10cm The number of turns per unit…

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Q: A 550-turn solenoid, 28 cmcm long, has a diameter of 2.3 cmcm . A 18-turn coil is wound tightly…

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Q: An alternator turns 1800 revolutions per minute. There are 300 turns and the magnetic flux in each…

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Q: A coil of 15 turns and radius 10.0 cm surrounds a long solenoid of radius 2.30 cm and 1.00 x 103…

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Q: A coil of 15 turns and radius 10.0 cm surrounds a long solenoid of radius 2.40 cm and 1.00*103…

A: It is given that, the number of turns of the coil is N=15radius of the coil(r) =10 cm=0.1 mcurrent…