A soil profile is shown in Figure P3.3 along with the stan- dard penetration numbers in the clay layer. Use Eqs. (3.8b) and (3.9) to determine the variation of c, and OCR with depth. What is the average value of c, and OCR? Dry sand y = 16.5 kN/m³ Си 0.24N72 Pa 1.5 m Groundwater (3.8b) table Sand The overconsolidation ratio, OCR, of a natural clay deposit can also be corre- lated with the standard penetration number. On the basis of the regression analysis of 110 data points, Mayne and Kemper (1988) obtained the relationship 1.5 m N60 Ysat = 19 kN/m³ 1.5 m • 8 Clay Ysat = 16.8 kN/m³ 1.5 m NEo 0.689 1N60 OCR = 0.193 (3.9) * A•8 1.5 m • 9 1.5 m 10 Sand FIGURE P3.3
A soil profile is shown in Figure P3.3 along with the stan- dard penetration numbers in the clay layer. Use Eqs. (3.8b) and (3.9) to determine the variation of c, and OCR with depth. What is the average value of c, and OCR? Dry sand y = 16.5 kN/m³ Си 0.24N72 Pa 1.5 m Groundwater (3.8b) table Sand The overconsolidation ratio, OCR, of a natural clay deposit can also be corre- lated with the standard penetration number. On the basis of the regression analysis of 110 data points, Mayne and Kemper (1988) obtained the relationship 1.5 m N60 Ysat = 19 kN/m³ 1.5 m • 8 Clay Ysat = 16.8 kN/m³ 1.5 m NEo 0.689 1N60 OCR = 0.193 (3.9) * A•8 1.5 m • 9 1.5 m 10 Sand FIGURE P3.3
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A soil profile is shown in Figure P3.3 along with the stan-
dard penetration numbers in the clay layer. Use Eqs. (3.8b)
and (3.9) to determine the variation of c, and OCR with
depth. What is the average value of c, and OCR?
Dry sand
y = 16.5 kN/m³
Си
0.24N72
Pa
1.5 m
Groundwater
(3.8b)
table
Sand
The overconsolidation ratio, OCR, of a natural clay deposit can also be corre-
lated with the standard penetration number. On the basis of the regression analysis of
110 data points, Mayne and Kemper (1988) obtained the relationship
1.5 m
N60
Ysat = 19 kN/m³
1.5 m
• 8
Clay
Ysat = 16.8 kN/m³
1.5 m
NEo 0.689
1N60
OCR = 0.193
(3.9)
* A•8
1.5 m
• 9
1.5 m
10
Sand
FIGURE P3.3
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