A soil profile consists of 6 m sand followed by 8 m of clay. In Scenario 1, the groundwater table is located at 2.0 m below the ground surface, as shown in Figure 1a. In Scenario 2, the groundwater table rises 2.0 m above the ground surface, as shown in Figure 1b. For each scenario: a). Calculate the total stress, the PWP, and the effective stress at depths of 0, 2, 6, 10, and 14 m below the ground surface. b). Plot the total stress, the PWP, and the effective stress variation with depth below the ground surface (on the same plot). a) Scenario 1 OK 2 m 4 m 8m Sand Clay y 18.7 kN/m³ sub 10.5 kN/m³ W = 56% G = 2.75 DO b) Scenario 2 2 m 6 m 8m Sand Clay Figure 1. Subsurface profile and layer characteristics sub 10.5 kN/m³ W = 56% G = 2.75
A soil profile consists of 6 m sand followed by 8 m of clay. In Scenario 1, the groundwater table is located at 2.0 m below the ground surface, as shown in Figure 1a. In Scenario 2, the groundwater table rises 2.0 m above the ground surface, as shown in Figure 1b. For each scenario: a). Calculate the total stress, the PWP, and the effective stress at depths of 0, 2, 6, 10, and 14 m below the ground surface. b). Plot the total stress, the PWP, and the effective stress variation with depth below the ground surface (on the same plot). a) Scenario 1 OK 2 m 4 m 8m Sand Clay y 18.7 kN/m³ sub 10.5 kN/m³ W = 56% G = 2.75 DO b) Scenario 2 2 m 6 m 8m Sand Clay Figure 1. Subsurface profile and layer characteristics sub 10.5 kN/m³ W = 56% G = 2.75
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A soil profile consists of 6 m sand followed by 8 m of clay. In Scenario 1, the
groundwater table is located at 2.0 m below the ground surface, as shown in Figure 1a.
In Scenario 2, the groundwater table rises 2.0 m above the ground surface, as shown
in Figure 1b.
For each scenario:
a).
Calculate the total stress, the PWP, and the effective stress at depths of 0, 2,
6, 10, and 14 m below the ground surface.
b). Plot the total stress, the PWP, and the effective stress variation with depth
below the ground surface (on the same plot).
a) Scenario 1
V
2 m
4 m
8 m
Sand
Clay
y = 18.7 kN/m³
Ysub 10.5 kN/m³
w = 56%
G = 2.75
▼
b) Scenario 2
2 m
6 m
8m
Sand
Clay
Figure 1. Subsurface profile and layer characteristics
sub 10.5 kN/m³
w = 56%
G₂ = 2.75
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VIEWStep 2: Calculate total and effective vertical stress along with PWP for scenario 1
VIEWStep 3: Calculate total and effective vertical stress along with PWP for scenario 2
VIEWStep 4: b) Plot the variation of total stress, effective vertical stress and PWP for both scenario
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