Answered: A sodium hydroxide solution that…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A sodium hydroxide solution that contains 23.9 grams of NaOH per L of solution has a density of 1.16 g/mL. Calculate the molality of the NaOH in this solution.

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$M o l a l i t y = \frac{N o . o f m o l e s o f s o l u t e \times 1000}{m a s s o f s o l v e n t i n g} G i v e n m a s s = 23.9 g M o l a r m a s s = 40 g / m o l N o . o f m o l e s o f s o l u t e = \frac{G i v e n m a s s}{m o l a r m a s s} = \frac{23.9}{40} = 0.59 m o l ρ = 1.16 g / m o l m a s s o f s o l u t i o n = d e n s i t y \times v o l u m e o f s o l u t i o n = 1.16 g / m l \times 1000 m l = 1160 g$

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